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3 years ago

12x5 – 10x2 + x – 45

1 answer:

6 0

(a)
$12x ^{5} - 10x ^{2} + x - 45$
(b)we have 4 terms in this expression.
(c)+12 is the leading coefficient in
$12x ^{5}$

(d) constant is -45

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Please help me thank you. 16 points and show all work.

Solnce55 [7]

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3 years ago

It costs a general admission fee of $6 to get into the fair and then $1 for each ride. Which of the following equations would re

joja [24]

Answer:

6+1x=y

Step-by-step explanation:

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3 years ago

Solve for y: 4x - 5y = 23

Eddi Din [679]

Answer:

4x - 5y = 0

Step-by-step explanation:

First off all you do it like this

4x - 5y = 23

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3 years ago

Read 2 more answers

carla can type 265 characters a minute on her keyboard. at that rate, how many characters can she type in 15 minutes?

gavmur [86]

Therefore multiply 265 by 15.

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3 years ago

Assume that BK Call Center receives 2 phone calls in one hour on average. If the department works 10 hours a day receiving the c

MrMuchimi

Using the Poisson distribution, the probabilities are given as follows:

A. 0.0888 = 8.88%.

B. 0.1354 = 13.54%.

C. 0.8646 = 86.46%.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Item a:

10 hours, 2 calls per hour, hence the mean is given by:

$\mu = 2 \times 10 = 20$ .

The probability is P(X = 20), hence:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 20) = \frac{e^{-20}20^{20}}{(20)!} = 0.0888$

Item b:

1 hour, hence the mean is given by:

$\mu = 2$

The probability is P(X = 0), hence:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-2}2^{0}}{(0)!} = 0.1354$

Item c:

The probability is:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1354 = 0.8646$

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

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2 years ago