Answer:
h(x) = -16x² + 192x + 208
784ft
6 sec
13 sec
Step-by-step explanation:
a)
h(x) = -16x² +vx + h
here v represent velocity
represent initial height of launch
h(x) = -16x² + 192x + 208
b)
h(x) = -16x² + 192x + 208
here a = -16
b = 192
c = 208
x = -b/2a
= -192/2(-16)
= 6
plug this value in the equation
h(x) = -16(6)² + 192(6) + 208
= 784ft
e)
Plug h(x)=0 in the equation
0 = -16x² + 192x + 208
divide equation by -16
x² - 12x - 13 = 0
Factors
1x * -13x = -13
1x - 13x = -12
Factorised form
x² - 12x - 13 = 0
x² + x - 13x - 13 = 0
x(x+1) -13(x+1) = 0
(x+1)(x-13) = 0
x = -1
x = 13
Since time can not be negative so we will reject x = -1
Answer- Yes it is a right triangle.
You can use the Pythagorean Theorem.
( a^2 + b^ = c^2 ) and replace a with 10, b with 24, and c with 26 and the equation will be balanced on both sides.
(10^2 + 24^2 = 26^2)
(100 + 576 = 676 )
Step 1. Factor out common terms in the first two terms, then in the last two terms.
2x^2(x - 5) -5(x - 5)
Step 2. Factor out the common term x - 5
(x - 5)(2x^2 - 5)
8x+3=43
-3 -3
8x=40
/8 /8
X=5