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3 years ago

What does the slope of distance vs. time graph show you about the motion graph

1 answer:

3 0

The principle is that the slope of the line on a position-time graph reveals useful information about the velocity of the object If the velocity is changing, then the slope is changing (i.e., a curved line). If the velocity is positive, then the slope is positive (i.e., moving upwards and to the right).

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the comparison of the number of atoms in a copper coin the size of a penny with the number of people on earth is made to illustr

vampirchik [111]

The atoms are very small hope this helps.

5 0

3 years ago

Read 2 more answers

The titration of Na2CO3 with HCl has the following qualitative profile: a. Identify the major species in solution at points A-F.

exis [7]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.

a) We need to find the major species from A to F.

Major Species at A:

1. $Na_{2} CO_{3}$

Major Species at B:

1. $Na_{2} CO_{3}$

2. $NaHCO_{3}$

Major Species at C:

1. $NaHCO_{3}$

Major Species at D:

1. $NaHCO_{3}$

2. $H_{2}CO_{3}$

Major Species at E:

1. $H_{2}CO_{3}$

Major Species at F:

1. $H_{2}CO_{3}$

b) pH calculation:

At Halfway point B:

pH = pK $a_{1}$ + log[ $CO_{3}$ $.^{-2}$ ]/[H $CO_{3}$ $.^{-1}$ ]

pH = pK $a_{1}$ = 6.35

Similarly, at halfway point D.

At point D,

pH = pK $a_{2}$ + log [H $CO_{3}$ $.^{-1}$ ]/[H2 $CO_{3}$ ]

pH = pK $a_{2}$ = 10.33

8 0

3 years ago

Which BEST describes the difference between speed and velocity? A) Velocity is instantaneous.

aleksandrvk [35]

Answer:

Option D describe the best this statement .

Explanation:

As velocity is the quantity which includes the rate of change as well as direction

3 0

3 years ago

Read 2 more answers

If 36 000 kg of full cream milk containing 4% fat is to be separated in a 6 hour period into skim milk with 0.45% fat and cream

Yuri [45]

Answer:

B=5522.33kg/h

C=478.11kg/h

Explanation:

Hi! It's a mass balance. First we have to determine the inflow.

mass flow rate = 36000kg / 6h = 6000kg / h

We define the input variable

- input flow (A) = 6000kg / h

-XgA = percentage of fat in A = 0.04

We define output variables.

- skim milk (B)

-creme (C)

-XgB = fat percentage at B = 0.0045

-XgC = percentage of fat in C = 0.45

Then we can start with the balance.

As a general rule, the mass balance is:

Input = Output

Balance sheet

1) A = B + C

Fat balance

2) A * XgA = B * XgB + C * XgC

Now we can solve.

We replace and clear B in equation 2

6000kg / h * 0.04 = B * 0.0045 + C * 0.45

B = (240kg / h) /0.045-C*0.45/0.0045

3) B = 53333.33kg / h-C * 100

We replace equation 3 in 1 and clear C

A = B + C

6000kg / h = 53333.33kg / h-C * 100 + C

C=(6000kg/h-53333.33kg/h)/(-99)

C=478.11kg/h

We replace C in equation 3 and calculate B

B = 53333.33kg / h-478.11kg/h * 100

B=5522.33kg/h

Then we have the values of the outflows.

C=478.11kg/h

B=5522.33kg/h

7 0

3 years ago

4 A Small rock

vodomira [7]

3 millimeters is the rock

6 0

3 years ago