Answer:
P' = 41.4 mmHg → Vapor pressure of solution
Explanation:
ΔP = P° . Xm
ΔP = Vapor pressure of pure solvent (P°) - Vapor pressure of solution (P')
Xm = Mole fraction for solute (Moles of solvent /Total moles)
Firstly we determine the mole fraction of solute.
Moles of solute → Mass . 1 mol / molar mass
20.2 g . 1 mol / 342 g = 0.0590 mol
Moles of solvent → Mass . 1mol / molar mass
60.5 g . 1 mol/ 18 g = 3.36 mol
Total moles = 3.36 mol + 0.0590 mol = 3.419 moles
Xm = 0.0590 mol / 3.419 moles → 0.0172
Let's replace the data in the formula
42.2 mmHg - P' = 42.2 mmHg . 0.0172
P' = - (42.2 mmHg . 0.0172 - 42.2 mmHg)
P' = 41.4 mmHg
Answer:
The molecular formula of an ascenapthalene is 
Explanation:
where,
=Elevation in boiling point = 
Mass of acenapthalene = 0.515 g
Mass of 
= 15.0 g = 0.015 kg (1 kg = 1000 g)
= boiling point constant = 3.63 °C/m
m = molality
Now put all the given values in this formula, we get
Let the molecule formula of the Acenapthalene be ![C_{6n]H_{5n}](https://tex.z-dn.net/?f=C_%7B6n%5DH_%7B5n%7D)
n = 2.0
The molecular formula of an ascenapthalene is
Answer:
There is 541.6 grams of calcium carbonate produced from 5.11 moles
Explanation:
Step 1: Data given
Number of moles of sodium carbonate ( Na2CO3) = 5.11 moles
Molar mass of sodium Carbonate:
⇒ Molar mass of Sodium = 22.99 g/mole
⇒ Molar mass of Carbon = 12.01 g/mole
⇒ Molar mass of Oxygen = 16 g/mole
Molar mass of Na2CO3 = 2* 22.99 + 12.01 + 3*16 = 105.99 g/mole
Step 2: Calculate mass of 5.11 moles of sodium carbonate
mass = number of moles of sodium carbonate * Molar mass of sodium carbonate
mass = 5.11 moles * 105.99 g/moles = 541.6 grams ≈ 542 grams
There is 541.6 grams of calcium carbonate produced from 5.11 moles Na2CO3
The answer would be 1.86 x 10^4
Phospholipids and embedded proteins make up the cell membrane.
