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DerKrebs [107]
3 years ago
12

450 nanometers to meters

Chemistry
1 answer:
lys-0071 [83]3 years ago
4 0

Answer: 4.5 x 10e-7

Explanation: 450 x 1e+9 = correct answer

Multiply amount of nanometers by 1e+9 to get the approximate result in meters.

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A solution is made by dissolving 0.565 g of potassium nitrate in enough water to make up 250. mL of solution. What is the molari
aalyn [17]
<h3>Molar mass of Potassium Nitrate:-</h3>

\\ \large\sf\longmapsto KNO_3

\\ \large\sf\longmapsto 39u+14u+3(16u)

\\ \large\sf\longmapsto 53u+48u

\\ \large\sf\longmapsto 101u

\\ \large\sf\longmapsto 101g/mol

Now

\boxed{\sf No\:of\:moles=\dfrac{Given\:mass}{Molar\:mass}}

\\ \large\sf\longmapsto No\:of\:moles=\dfrac{0.565}{101}

\\ \large\sf\longmapsto No\:of\:moles=0.005mol

We know

\boxed{\sf Molarity=\dfrac{Moles\:of\:solute}{Vol\:of\:Solution\:in\:L}}

\\ \large\sf\longmapsto Molarity=\dfrac{0.005}{\dfrac{250}{1000}L}

\\ \large\sf\longmapsto Molarity=\dfrac{0.005}{0.250}

\\ \large\sf\longmapsto Molarity=0.02M

8 0
3 years ago
Read 2 more answers
A student prepares two solutions as shown. The dots represent solute particles. The student wants to test the conductivity of ea
stealth61 [152]

Answer:

I think its D

Explanation:

It cant be B or C bc the solute particles arent changing. And  its not A because the concentration isnt constant

3 0
2 years ago
Fill in the blank: in space, astronauts experience ________ which is the apparent loss of weight of an object that is falling in
jeka57 [31]
Astronauts experience weightlessness which is the apparent loss of weight of an object that is falling in gravitational field
3 0
3 years ago
Consider this equilibrium: COCl2(g) CO(g) + Cl2(g) Keq = 8.1 x 10-4. What is true for this system?
fiasKO [112]
Answer is: [COCl₂] > [CO][Cl₂]
Chemical reaction: COCl₂(g) ⇄ CO(g) + Cl₂(g); Keq = 8.1 x 10⁻⁴.
Keq = [CO] · [Cl₂] / [COCl₂]; equilibrrium constant of chemical reaction.
[CO] · [Cl₂] / [COCl₂] = 0,00081.
Equilibrium product concentration is much more less than equilibrium concentration of reactant.

6 0
3 years ago
30g of naoh is dissolved in 1.5 liter solution the active mass of naoh is?
Pepsi [2]

Answer:

0.5mol/L

Explanation:

First, let us calculate the number of mole NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the question = 30g

Number of mole = Mass /Molar Mass

Number of mole = 30/40 = 0.75mol

Volume = 1.5L

Active mass = mole/Volume

Active mass = 0.75mol/1.5L

Active mass = 0.5mol/L

7 0
3 years ago
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