Answer:A -3,6
Step-by-step explanation: Substitue the answers in and they work out
To find out if they are parallel we need to see if the gradient is the same, to do this we need to get y in terms of x:
assuming the first equation is x+y+7=0
y=-x-7
and
y=x-3
The gradient is the coefficient of x (the number infront of x)
For equation 1 the gradient is -1, and for number 2 it is 1, therefore they are not parallel.
However to check if they are perpendicular we need to see if their gradients multiply to equal -1.
-1*1=-1 therefore they are perpendicular
Answer:
Step-by-step explanation:
y = (x^2 + 4x) + 2
Take 1/2 of the linear term 4/2 = 2 and square that result. 2^2 = 4.
Put it after 4x
y = (x^2 + 4x + 4) +2 Subtract what you put inside the brackets on the outside.
y = (x^2 + 4x + 4) + 2 - 4 Combine the right.
y = (x^2 + 4x + 4) - 2 Express the brackets as a square.
y = (x + 2)^2 - 2
That's your answer
a = 1
h = 2
k = -2
Step-by-step explanation:
8t³-80t²+200t
= 8(t³-10t+25)
= 8t(t²-10t+25)
= 8t(t-5)(t-5)
= 8t(t-5)²
the answer is B.