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QveST [7]
3 years ago
13

According to Avogadro's law how many molecules of any gas at STP are present in a volume of 22.41 L?

Chemistry
2 answers:
Mice21 [21]3 years ago
7 0
At STP (standard temperature and pressure), one mole of a gas occupies 22.41 liters of volume. Avogadro's number (6.022*10^23) is the number of molecules per mole of a substance, or one mole of anything really. This means there are 6.022*10^23 molecules of any gas with a volume of 22.41 L at STP.
DiKsa [7]3 years ago
5 0
At STP, Pressure = 1atm, temperature = 278K, R= 0.082 litre-atm-(mol-K) ^-1. V= 22.4L. Applying gas equation, PV=nRT. n = PV/RT = 1x22.4/0.082x278 = 1mole. Number of molecules of gas= moles x Avogadro's number = 1x6.02x10^23 = 6.02x10^23.
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Explanation:

Molar mass

The mass present in one mole of a specific species .

The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .

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Molar mass of  S₈ = 8 * 32 g/mol.  = 256 g/mol.

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Molar mass of of the atoms are -

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Molar mass of of the atoms are -

Carbon , C = 12 g/mol

oxygen , O = 16 g/mol.

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dexar [7]

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