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3 years ago

A system of equations has no solution. If y = 8x + 7 is one of the equations, which could be the other equation?

1 answer:

5 0

For the answer to the question above, a system of equations has no solution when the lines representing the equation are parallel but do not coincide. For two lines to be parallel, the must have the same gradient i.e. coefficient of x when y is made the subject of formula must be equal.
If one of the equations is
y = 8x + 7,
then the other equation will be
y = 8x - 7

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What is the value of x? Round to the nearest tenth. Please Help

Elodia [21]

Answer:

Step-by-step explanation:

The segment 20.2 cm is the tangent. Therefore x and 20.2cm are perpendicular.

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=x,\ leg=20.2cm,\ hypotenuse=(14.7+x)cm$

Substitute:

$x^2+20.2^2=(14.7+x)^2$ <em>use (a + b)² = a² + 2ab + b²</em>

$x^2+408.04=14.7^2+(2)(14.7)(x)+x^2$ <em>subtract x² from both sides</em>

$408.04=216.09+29.4x$ <em>subtract 216.09 from both sides</em>

$191.95=29.4x$ <em>divide both sides by 29.4</em>

$x\approx6.5\ cm$

7 0

4 years ago

Find the measure of the indicated angle to the nearest degree

omeli [17]

$\boxed{\sf sin\Theta=\dfrac{P}{H}}$

$\\ \sf\longmapsto sin\Theta=\dfrac{16}{26}$

$\\ \sf\longmapsto sin\Theta=\dfrac{8}{13}$

$\\ \sf\longmapsto sin\Theta=0.5$

Convert to p/q form

$\\ \sf\longmapsto sin\Theta=\dfrac{5}{10}$

$\\ \sf\longmapsto sin\Theta=\dfrac{1}{2}$

$\\ \sf\longmapsto sin\Theta=sin30$

$\\ \sf\longmapsto \Theta\approx30°$

4 0

3 years ago

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

In the 2012 presidential election, exit polls from the critical state of Ohio provided the following results:

neonofarm [45]

Answer:

50% probability that a randomly selected respondent voted for Obama.

Step-by-step explanation:

We have these following probabilities:

60% probability that an Ohio resident does not have a college degree.

If an Ohio resident does not have a college degree, a 52% probability that he voted for Obama.

40% probability that an Ohio resident has a college degree.

If an Ohio resident has a college degree, a 47% probability that he voted for Obama.

What is the probability that a randomly selected respondent voted for Obama?

This is the sum of 52% of 60%(non college degree) and 47% of 40%(college degree).

$P = 0.52*0.6 + 0.47*0.4 = 0.5$

50% probability that a randomly selected respondent voted for Obama.

8 0

3 years ago

using a table of values determine the solution to the equation below to the nearest fourth of a unit.

DedPeter [7]

Answer:

सॉरी भाई जल्द ही देखिये अलविदाIl existe de nombreux exemples de portfolios d’artistes en ligne. Trouvez-en un et partagez un lien vers celui-ci. En vous basant sur le portfolio, écrivez quelques phrases évaluant l'artiste. S'il y a les réponses d'autres élèves sur le forum de discussion, examinez-les et voyez si vous êtes d'accord ou pas d'accord avec leur opinion sur le travail des artistes.

3 0

3 years ago

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