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il63 [147K]
2 years ago
8

Help me get this right.

Mathematics
1 answer:
maria [59]2 years ago
6 0

Answer:

A. 5/2

Step-by-step explanation:

Can't be c or d since those are negative and b would have a much steeper slope rise over run is how you find side the two points connect by going up 5 and over 2

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How do you solve this
fiasKO [112]
(((x + y) / 3) + (1 / x)) / (5 + (15 / x))
The best way is to make it one fraction.
Multiply by ((3x/3x) / (3x/3x)) to remove the other fractions.
((x(x + y)) + 3(1)) / (5(3x) + 3(15))
(x^2 + xy + 3) / (15x + 45)
Then factor to simplify
(x^2 + xy + 3) / (3(x + 15))



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3 years ago
Which of the given points would be in a table generated by the equation below?
Sergeeva-Olga [200]
B. (0,s/q) ........................................................
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3 years ago
What is the square root of pi
Elena L [17]
1.77245385
that is the answer
3 0
3 years ago
Read 2 more answers
Is 4 a solution of2=8
JulsSmile [24]

Answer:

Two doesn’t equal 8. Theoretically, eight is the solution...

Step-by-step explanation:

5 0
3 years ago
Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)
andrew11 [14]
Use the distance formula.

\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}

 
Points S and W.
\sqrt{(3)^2 + (2)^2}

\sqrt{9+4}

\sqrt{13}

~3.6

Points S and T
\sqrt{(3 - 0)^2 + (-2 - 0)^2}

\sqrt{(3)^2 + (-2)^2}

\sqrt{9+4}

\sqrt{13}

~3.6

Points T and U
\sqrt{(3 - 2)^2 + (-2 + 5)^2}

\sqrt{(1)^2 + (3)^2}

\sqrt{1+9}

\sqrt{10}

~3.1

Points U and V
\sqrt{(2+2)^2 + (-5 + 5)^2}

\sqrt{(4)^2 + (0)^2}

\sqrt{16}

~4

Points V and W
\sqrt{(-2+3)^2 + (-5 + 2)^2}

\sqrt{(1)^2 + (-3)^2}

\sqrt{2+9}

\sqrt{11}

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17
4 0
3 years ago
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