The only incorrect statement is C)
The athlete was biking between [1,3] and running between [3,6]. The durations of 2 and 3 are not equal.
Answer:
The prices at which manager predict that at least 55 hats will be sold would be would be of $38
Step-by-step explanation:
According to the given data we the following:
Number of hats sold at $18=115
The manager predicts at 3 less will sold for every rise in 1 $ for at least 55 hats.
Therefore, reduction in number=115 hats-55 hats=60
So, increase in price=reduction in number/number of hats manager predicts that will be sold for every $1 increase in price
increase in price=60/3=$20
Therefore, prices at which manager predict that at least 55 hats will be sold would be=$18+$20=$38
The prices at which manager predict that at least 55 hats will be sold would be would be of $38
First divide the coefficients:-
-18 / -12 = 3/2
a^-2 / a^-4 = a^2
b^-5 / b^-6 = b
so the expression simplifies to 3a^2b / 2
Answer:
t > -7
Step-by-step explanation:
To solve for t, first add 5 to both sides:
-2t - 5 < 9
-2t < 14
Divide each side by -2, and flip the inequality because we are dividing by a negative number:
-2t < 14
t > -7
So, the solution is t > -7
