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anygoal [31]
2 years ago
10

Colin buys a car for £42800. It depreciates at a rate of 5% per year. How much will it be worth in 2 years? Give your answer to

the nearest penny where appropriate.​
Mathematics
1 answer:
11111nata11111 [884]2 years ago
7 0

Principal=₹42800

Rate of interest=5% but 2 years so multiply by 2 =5×2=10%

Time=2 years

Simple interest=42800×10×2/100= ₹8560

Amount=42800+8560=Rs51360

The answer is ₹ 51360

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(b) Write 3*3*3*3* 3 as a single power of 3
algol13

Answer:

3⁵

Step-by-step explanation:

3×3×3×3×3=3⁵

You have a mutiplication. The base is 3, the exponent is the count of how many 3 you have. In this multiplication 3 appears 5 times, so 3⁵.

5 0
3 years ago
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18-2x=4x drag AND drop the reasons into the boxes to correctly complete the table.
scoundrel [369]
18-2x=4x is given
18=6x is addition property of equality
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4 0
3 years ago
Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
3 years ago
Read 2 more answers
What is the value of (2/3)-4
Angelina_Jolie [31]

Answer:

16/81

Step-by-step explanation:

as there is (-) sign so when we multiply even negative numbers it becomes positive

8 0
3 years ago
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Describe an algorithm for finding the smallest integer in a finite sequence of natural numbers.
Crazy boy [7]

Answer:

min = a_1

for i:= 2 to n:

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return min

Step-by-step explanation:

We call the algorithm "minimum" and a list of natural numbers a_1, a_2, \cdot\cdot\cdot, a_n.

So lets first set the minimum to a_1

min = a_1

now we want to check all the other numbers.

We can use a simple for loop, to find the minimum

min = a_1

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5 0
1 year ago
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