Answer:
To the nearest hundred dollars, the car will be worth $17,900 by 2005
Step-by-step explanation:
Firstly, we need to write the depreciation equation
We have this as:
V = I(1 - r)^t
V is the present value which is what we want to calculate
I is the initial value, the amount the cad was bought which is $22,000
r is the rate of change which is 5% = 5/100 = 0.05
t is the time difference which is 2005-2001 = 4
Substituting all these into the depreciation equation, we have it that
V = 22,000(1 -0.05)^4
V = $17,919.1375
To the nearest hundred dollars, that would be;
$17,900
Answer: 2 or 11 if trick question
Step-by-step explanation: just put 1 and 1 together
1 worker = 30 hours a week
1 worker = 30 x $5.50 a week = $165
1 worker = $165
1000 workers = 165 x 1000 = $165 000
Answer:
x = -1/7
Step-by-step explanation:
Solve for x
9-17x-5-4x=7
Combine like terms
-21x +4 = 7
Subtract 4 from each side
-21x-4+4 = 7-4
-21x = 3
Divide each side by -21
-21x/-21 = 3/-21
x = -1/7
Check
9 - 17(-1/7) -5 -4(-1/7) =7
9 + 17/7 -5 + 4/7 =7
4 +21/7 = 7
4+3 = 7
7=7
