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3 years ago

Mai has a rectangular poster that is 18 centimeters long and 15 centimeters wide. What is the area of the poster in square

Mathematics

1 answer:

slavikrds [6]3 years ago

8 0

Answer:

270 centimeters

Step-by-step explanation:

A = wl

A = 15 cm x 18 cm

A = 270 centimeters

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Refer to the accompanying TI-83/84 Plus calculator display of a 95% confidence interval. The sample display results from using a

nikklg [1K]

Answer:

The confidence interval is $22.805$

Step-by-step explanation:

We have given,

The Z interval (23.305,25.075)

Mean $\bar{x}=23.69$

Sample n=30

To find : The confidence interval?

Solution :

We know, The confidence interval is in the format of

$\bar{x}-E$

E denotes the margin of error,

$E=\frac{U-L}{2}$

Where, U is the upper limit U=25.075

L is the lower limit L=23.305

$E=\frac{25.075-23.305}{2}$

$E=\frac{1.77}{2}$

$E=0.885$

Substitute the value of E and $\bar{x}$ in the formula,

$23.69-0.885$

$22.805$

Therefore, The confidence interval is $22.805$

8 0

3 years ago

What is now the length in meters?

Natasha_Volkova [10]

I think length is 7－x.

5 0

3 years ago

Read 2 more answers

2 3/4-3 3/8÷4 1/2 plus show ur work

sladkih [1.3K]

Answer:

149/60

Step-by-step explanation:

11/4-27/8*1/4*1/2

11/4-27/64

149/64

8 0

3 years ago

Find the missing side. Round to the nearest tenth.

Firdavs [7]

Answer: 23.7

Step-by-step explanation:

Let's calculate the acute angle at the base of the triangle:

180° - 90° - 40° = 50°

Find side x:

$\dfrac{sin \: 90^{o} }{31} =\dfrac{sin \: 50^{o} }{x}\\\\sin \: 90^{o} \cdot x=sin \: 50^{o} \cdot 31\\\\sin \: 90^{o} =1\\sin \: 50^{o} \approx 0.766\\1 \cdot x =0.766 \cdot 31\\x=23.746\\23.746 \approx 23.7$

5 0

2 years ago

Solve for x: log x + log 8 = 2

likoan [24]

Answer: The answer is 252

Step-by-step explanation:

:)))

8 0

2 years ago

Read 2 more answers