This is an arithmetic sequence because each term is 7 greater than the previous term, so 7 is what is called the common difference...

Any arithmetic sequence can be expressed as:

a(n)=a+d(n-1), a=first term, d=common difference, n=term number.

We know a=1 and d=7 so:

a(n)=1+7(n-1)

a(n)=1+7n-7

a(n)=7n-6

The above is the "rule" for the nth term.

8 0

3 years ago

Read 2 more answers

Help please (will chose brainliest).

lara [203]

Answers with Explanation.

i. If we raise a number to an exponent of 1, we get the same number.

${10}^{1} = 10$

ii. If we raise 10 to an exponent of 2, it means we multiply 10 by itself two times.

${10}^{2} = 10 \times 10 = 100$

iii. If we raise 10 to an exponent of 3, it means we multiply 10 by itself three times.

${10}^{3} = 10 \times {10}^{2} = 10 \times 100 = 1000$

iv. If we raise 10 to an exponent of 4, it means we multiply 10 by itself four times.

${10}^{4} = 10 \times {10}^{3} = 10 \times 1000 = 10000$

v. If we raise 10 to an exponent of 5, it means we multiply 10 by itself five times.

${10}^{5} = 10 \times {10}^{4} = 10 \times 10000 = 100000$

${10}^{5} = 100000$

vi. Recall that,

${a}^{ - m} = \frac{1}{ {a}^{m} }$
We apply this law of exponents to obtain,

${10}^{ - 2} = \frac{1}{{10}^{2} } = \frac{1}{100}$

vii. We apply
${a}^{ - m} = \frac{1}{ {a}^{m} }$
again to obtain,

${10}^{ - 3} = \frac{1}{ {10}^{3} } = \frac{1}{1000}$

5 0

3 years ago

Can y’all help me on num 15

alex41 [277]

Answer:

the answer is 2x+2

Step-by-step explanation:

you have to distribute the two equations and add the common factors together.

8 0

3 years ago