How would you classify an employee who communicates effectively, listens to coworkers, and makes good decisions?

What do you mean by HDML coding

castortr0y [4]

Answer:

hdml coding is a standard markup language for documents designed to be displayed in a web browser.

Explanation:

it can be assisted using things like CSS or JS

8 0

3 years ago

at the grocery store alexa by 1 1/3 lb of ground turkey nasha by two times as much ground turkey is alexa how much ground turkey

Alexeev081 [22]

tasha buys 2 2/3 much ground turkey

8 0

3 years ago

Assume a TCP sender is continuously sending 1,090-byte segments. If a TCP receiver advertises a window size of 5,718 bytes, and

Arturiano [62]

Answer:

for the 5 segments, the utilization is 3.8%

Explanation:

Given the data in the question;

segment size = 1090 bytes

Receiver window size = 5,718 bytes

Link transmission rate or Bandwidth = 26 Mbps = 26 × 10⁶ bps

propagation delay = 22.1 ms

so,

Round trip time = 2 × propagation delay = 2 × 22.1 ms = 44.2 ms

we determine the total segments;

Total segments = Receiver window size / sender segment or segment size

we substitute

Total segments = 5718 bytes / 1090 bytes

Total segments = 5.24587 ≈ 5

Next is the throughput

Throughput = Segment / Round trip

Throughput = 1090 bytes / 44.2 ms

1byte = 8 bits and 1ms = 10⁻³ s

Throughput = ( 1090 × 8 )bits / ( 44.2 × 10⁻³ )s

Throughput = 8720 bits / ( 44.2 × 10⁻³ s )

Throughput = 197.285 × 10³ bps

Now Utilization will be;

Utilization = Throughput / Bandwidth

we substitute

Utilization = ( 197.285 × 10³ bps ) / ( 26 × 10⁶ bps )

Utilization = 0.0076

Utilization is percentage will be ( 0.0076 × 100)% = 0.76%

∴ Over all utilization for the 5 segments will be;

⇒ 5 × 0.76% = 3.8%

Therefore, for the 5 segments, the utilization is 3.8%

4 0

3 years ago

Using Python I need to Prompt the user to enter in a numerical score for a Math Class. The numerical score should be between 0 a

yaroslaw [1]

Answer:

The program doesn't use comments; See explanation section for detailed line by line explanation

Program starts here

def lettergrade(subject,score):

print(subject+": "+str(score))

if score >= 90 and score <= 100:

print("Letter Grade: A")

elif score >= 80 and score <= 89:

print("Letter Grade: B")

elif score >= 70 and score <= 79:

print("Letter Grade: C")

elif score >= 60 and score <= 69:

print("Letter Grade: D")

elif score >= 0 and score <= 59:

print("Letter Grade: F")

else:

print("Invalid Score")

maths = int(input("Maths Score: "))

english = int(input("English Score: "))

pe = int(input("PE Score: "))

science = int(input("Science Score: "))

arts = int(input("Arts Score: "))

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Explanation:

The program makes the following assumptions:

Scores between 90–100 has letter grade A

Scores between 80–89 has letter grade B

Scores between 70–79 has letter grade C

Scores between 60–69 has letter grade D

Scores between 0–69 has letter grade E

Line by Line explanation

This line defines the lettergrade functions; with two parameters (One for subject or class and the other for the score)

def lettergrade(subject,score):

This line prints the the score obtained by the student in a class (e.g. Maths Class)

print(subject+": "+str(score))

The italicized determines the letter grade using if conditional statement

This checks if score is between 90 and 100 (inclusive); if yes, letter grade A is printed

if score >= 90 and score <= 100:

print("Letter Grade: A")

This checks if score is between 80 and 89 (inclusive); if yes, letter grade B is printed

elif score >= 80 and score <= 89:

print("Letter Grade: B")

This checks if score is between 70 and 79 (inclusive); if yes, letter grade C is printed

elif score >= 70 and score <= 79:

print("Letter Grade: C")

This checks if score is between 60 and 69 (inclusive); if yes, letter grade D is printed

elif score >= 60 and score <= 69:

print("Letter Grade: D")

This checks if score is between 0 and 59 (inclusive); if yes, letter grade F is printed

elif score >= 0 and score <= 59:

print("Letter Grade: F")

If input score is less than 0 or greater than 100, "Invalid Score" is printed

else:

print("Invalid Score")

This line prompts the user for score in Maths class

maths = int(input("Maths Score: "))

This line prompts the user for score in English class

english = int(input("English Score: "))

This line prompts the user for score in PE class

pe = int(input("PE Score: "))

This line prompts the user for score in Science class

science = int(input("Science Score: "))

This line prompts the user for score in Arts class

arts = int(input("Arts Score: "))

The next five statements is used to call the letter grade function for each class

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

7 0

2 years ago

Write an algorithm to sum to values

Elis [28]

Answer:

There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:

Let a,b be two numbers.

c=a+b;

print(c);

But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:

Let a be the variable where the input numbers are stored.

while(f==1)

{

printf(“Enter number”);

scanf(“Take number into the variable a”);

sum=sum+a;

printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);

scanf(“Take the input into the variable f”);

}

print(Sum)

Explanation:

hi there answer is given mar me as brainliest

5 0

3 years ago