Answer:
5x+8y
Step-by-step explanation:
We can first open the brackets by using the distrubitive propety.
2(x+4y)+3x
2x+8y+3x
Now we can combine like terms.
5x+8y.
I combined the 3x and the 2x. This works because imagined I have 3 of something then I got 2 more of that something I would now have 5 of that something.
Hoped this helped,
JoeLouis2
Answer:

So then the best option would be:
a. 1/25
Step-by-step explanation:
For this case we assume that the sample space for the numbers is :
![S_1= [A,B,C,D,E]](https://tex.z-dn.net/?f=%20S_1%3D%20%5BA%2CB%2CC%2CD%2CE%5D)
And the sample space for the numbers is:
![S_2 =[1,2,3,4,5]](https://tex.z-dn.net/?f=%20S_2%20%3D%5B1%2C2%2C3%2C4%2C5%5D)
Both sampling spaces with a size of 5.
We define the following events:
A="We select a 2 from the numbers"
B= "We select a E from the letters"
We can find the individual probabilities for each event like this:


And assuming independence we can find the probability required like this:

The last probability is the probability of obtain obtain a 2 AND an E
So then the best option would be:
a. 1/25
Answer:
2 19/24 feet
Step-by-step explanation:
14 5/8 = 14 15/24
17 5/12 = 17 10/24 ==> 16 34/24
16 - 14 = 2
34/24 - 15/24 = 19/24
Answer = 2 19/24 feet
Hope this helps!
-The Business Man
A. 10x<span>^18
Hope this helps!!!</span>
Answer:
u=11
Step-by-step explanation:
1. 36=47-9
36≠38
2. 36=47-11
36=36
3. 36=47-8
36≠39
4. 36=47-38
36≠9