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SCORPION-xisa [38]
3 years ago
5

At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist headi

ng north is riding 6 km/hour faster than the bicyclist heading south. At 10:15, they are 42.5 km apart. Find the two bicyclists’ rates.
Mathematics
1 answer:
Viktor [21]3 years ago
3 0

Answer: The rates of bicyclists of north and south are  20km/hr and 14km/hr respectively.

Step-by-step explanation:

Since we have given that

Let the speed of bicyclist heading south be 'x'.

Let the speed of bicyclist heading north be 'x+6'.

Since they are moving in opposite directions,

So, relative speed = x+x+6=2x+6

Time taken = 10: 15 to 9:00 = 1 hour 15 minutes = 1\dfrac{15}{60}=1\dfrac{1}{4}=\dfrac{5}{4}

Distance between them = 42.5 km

According to question, it becomes,

\dfrac{Distance}{time}=Speed\\\\\dfrac{42.5}{\dfrac{5}{4}}=2x+6\\\\42.5=\dfrac{5}{4}(2x+6)\\\\4\times 42.5=5(2x+6)=10x+30\\\\170=10x+30\\\\170-30=10x\\\\140=10x\\\\x=\dfrac{140}{10}\\\\x=14\ km/hr

Speed of bicyclist heading north would be 14+6=20 km/hr

So, the rates of bicyclists of north and south are  20km/hr and 14km/hr respectively.

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At the center of espionage in Kznatropsk one is thinking of a new method for sending Morse telegrams. Instead of using the tradi
alexgriva [62]

Answer:

It takes less time sending 5 letters the traditional way with a probability of 36.7%.

Step-by-step explanation:

First we must take into account that:

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Where L is the intensity in which the events happen in a time unit and x is the number of events.

To solve the problem we must calculate the probability of events  (to send 5 letters) in a unit of time for both methods, so:

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P(X=5)=\frac{1^{5}e^{-1}}{1!}\\\\P(X=5) = 0.367

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