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3 years ago

Jen and Maria have dance class at 3:45 . Write the time two different ways. Is it am or pm ? Explain

Mathematics

2 answers:

jonny [76]3 years ago

6 0

Dance class is at 3:45pm, because the dance studio would not be open that early.

V125BC [204]3 years ago

3 0

3:45 or 15:45. It is p.m. because they would not open that early in the morning

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You can afford a $950 per month mortgage payment. You've found a 30 year loan at 7% interest. a) How big of a loan can you affor

Lubov Fominskaja [6]

Based on the amount to be paid per month, the size of the loan you can afford is $142,792.19.

The total amount you pay to the loan company is $342,000.

The interest on the money is $199,207.81.

The size of the loan is the present value associated with that loan payment that you can afford:

950 = (7/12% x Present value) / ( 1 - (1 + 7/12%)⁻⁽³⁰ ˣ ¹²⁾

950 = (7/12% x Present value) / 0.8767

Present value = $142,792.19

The total amount of money paid is:

= Number of periods x Payment per period

= 30 years x 12 months per year x 950

= $342,000

The interest is:

= 342,000 - 142,792.19

= $199,207.81.

Find out more on interest payments on loans at brainly.com/question/13005100

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1 year ago

In august Janet's clothing store sold 234 shirts with the ratio of short sleeves to long sleeves being 9:4. how many short sleev

makvit [3.9K]

162 short sleeve shirts; if you add 9 and 4, you get 13. Then, divide 234 by 13, which equals 18. 18 multiplied by 9 is 162.

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3 years ago

99/101 as a repeating decimal using bar notation to indicate the repeating digits

Tamiku [17]

0.9801. The "9801" is repeatin so just draw the repeating bar above those numbers.

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3 years ago

Evaluate the expression when y = 5.<br><br> 3 + y + 6<br><br> 9<br><br> 14<br><br> 19<br><br> 21

REY [17]

Its prob b- 14 cause they all add up

6 0

3 years ago

Read 2 more answers

Start with the geometric power series LaTeX: 1+x+x^2+x^3+x^4+\cdots Substitute LaTeX: -x^3in place of LaTeX: x, and then take a

valina [46]

Answer:

$-3x^2+6x^5-9x^8+12x^{11}+...=\sum_{n=1}^{\infty }\left ( -1 \right )^n\,\,3n\,\,x^{3n-1}$

Step-by-step explanation:

Given : $1+x+x^2+x^3+x^4+\cdots$

On putting $-x^3$ in place of x , we get $1+\left ( -x^3 \right )+\left ( -x^3 \right )^2+\left ( -x^3 \right )^3+\left ( -x^3 \right )^4+...$

On simplifying , we get $1-x^3+x^6-x^9+x^{12}+...$

On differentiating , we get $\left ( 1-x^3+x^6-x^9+x^{12}+... \right )'=-3x^2+6x^5-9x^8+12x^{11}+...$

Here ,

$-3x^2=\left ( -1 \right )^1\,3(1)x^{3(1)-1}\\6x^5=\left ( -1 \right )^2\,\,3(2)\,\,x^{3(2)-1}\\-9x^8=\left ( -1 \right )^3\,\,3(3)\,\,x^{3(3)-1}\\12x^{11}=\left ( -1 \right )^4\,\,3(4)\,\,x^{3(4)-1}$

Now , we need to express it using summation notation.

$\left ( 1-x^3+x^6-x^9+x^{12}+... \right )'=-3x^2+6x^5-9x^8+12x^{11}+...=\sum_{n=1}^{\infty }\left ( -1 \right )^n\,\,3n\,\,x^{3n-1}$

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3 years ago