Answer: For the first it would be 6, 3, and 7, 6 is double 3, and 7 is 1 more than 6, 6+3=9, and 9+7=16.
The second one is there were only 6 days that students were absent as 12 divided by 2 is 6.
Answer:
n=-10/3
Step-by-step explanation:
"Twice the difference of a number n and seven is equal to four less than the product of five and the number n" translates into 2(n-7) = 5n - 4. To solve, isolate the variable n.
2(n-7) = 5n - 4
2n - 14 = 5n - 4
2n - 10 = 5n
-10 = 3n
-10/3 = n
Answer:
Try D because a number times 10 to the power of anything is not that number!
Step-by-step explanation:
Answer:
Reflection of ΔGBC on side BC.
Step-by-step explanation:
Transformation is the process by which the orientation or dimension of a given shape or figure is adjusted by some method of processes to produce an image with a required property.
From the given diagram, triangles ABC and GBC are congruent, so that;
AC ≅ GC
AB ≅ GB
BC is a common side to both triangles
Therefore, the appropriate transformation that would take ΔGBC onto ΔABC is reflection on side BC.
The data for linear pair are;
The domain are the values (input) on the x-axis which is the time
The range are the values input on the y-axis which is the height reached by the balloon
Part A
The interval of the domain during which the water balloon height is increasing is 0 ≤ x ≤ 2
Part B
The intervals of the domain the water balloon’s height stays the same are;
2 ≤ x ≤ 3 and 6 ≤ x ≤ 8
Part C
The water balloon height is decreasing at the following intervals;
At the interval 3 ≤ x ≤ 4
The rate of decrease = (20 ft. – 80 ft.)/(4 s – 3 s) = -20 ft./s.
At the interval 4 ≤ x ≤ 6
The rate of decrease = (0 ft. – 20 ft.)/(6 s – 4 s) = -10 ft./s
Therefore, the interval of the domain that the balloon’s height is decreasing the fastest is 3 ≤ x ≤ 4
Part D
According to Newton’s law of motion, provided that the no additional force is applied to the the balloon, at 10 seconds, the height of the water balloon is 0 ft. given that the height of the balloon is constantly decreasing from 3 seconds after being thrown off the roof, reaching a height of 0ft. at 6 seconds and maintaining that height up until 8 seconds.
By extending the graph further, the height of 0 ft. is obtained at 10 seconds after the balloon is thrown