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Studentka2010 [4]
3 years ago
9

7 + (a+b) = (7+a) +b what is the property

Mathematics
1 answer:
morpeh [17]3 years ago
4 0

Answer:

Associative property of addition

Step-by-step explanation:

To “associate” means to connect or join with something. According to the associative property of addition, the sum of three or more numbers remains the same regardless of how the numbers are grouped.

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Product is a 12 ounce bottle of generic mouthwash that sells $4.39 product B is a 24 ounce bottle of mouthwash that cost $2.79 w
Anna35 [415]
Hi there,
To compare we can look at the amount of (ounces)
A: 12         B:24
so as it appears B wins this part
Now price 
A: $ 4.39       B:$2.79
A is relatively expensive than B
B is cheaper with more ounces
A is less ounces and relatively expensive
which one would you buy?
5 0
3 years ago
A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so
Debora [2.8K]

Let A(t) = amount of salt (in pounds) in the tank at time t (in minutes). Then A(0) = 11.

Salt flows in at a rate

\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}

and flows out at a rate

\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}

which I'll solve with the integrating factor method.

\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95

-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}

\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}

Integrate both sides. By the fundamental theorem of calculus,

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)

\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}

\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}

\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}

After 1 hour = 60 minutes, the tank will contain

A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131

pounds of salt.

7 0
1 year ago
Do these numbers 19.657 < 19.67​
nexus9112 [7]
I dont understand your question.......
5 0
3 years ago
What is the quotient of -10 and -5?
Andreyy89

Answer:

2.

Step-by-step explanation:

-10 divided by -5 is 2.  The two negatives cancel each other out.

5 0
3 years ago
What's the angle of y and x ??
victus00 [196]
Y is going to be the number 40
x will equal 90
6 0
3 years ago
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