Current price : 600
Price 10 years from today :
P (10)=600×(1.037)^(10)=862.86
Answer:
50% of females do not satisfy that requirement
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

If a college includes a minimum score of 900 among its requirements, what percentage of females do not satisfy that requirement
This is scores lower than 900, which is the pvalue of Z when X = 900.
So



has a pvalue of 0.5
50% of females do not satisfy that requirement
I can do like 42, my highest was 54 though
Answer:
\log_{b}({b^x})=x
Step-by-step explanation:
hope this helps
Answer:
If your goal is to simplify it, then it would be
38Fmnsxi