Question

Solve y^2 + 4y - 32 = 0 using the zero product property.

Answer 1

Hello,

y²+4y-32=0
<==>y²+8y-4y-32=0
<==>y(y+8)-4(y+8)=0
<==>(y+8)(y-4)=0
<==> y=-8 or y=4
Sol={-8;4}
Answer A