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4 years ago

George found that he blinked 85 times in 15 minutes. At this rate, how many seconds passed during 51 blinks?

Mathematics

1 answer:

Juliette [100K]4 years ago

7 0

540 seconds which is equal to 9 minutes.

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Derivatives of sin(logx) from first principle

Nina [5.8K]

Answer:

cos(logx)*(1/x)

Step-by-step explanation:

(sin(logx))'=cos(logx)*logx'=cos(logx)*(1/x)

5 0

3 years ago

If you have distance and time how do you find speed?<br>

Maurinko [17]

Answer:

Divide distance by time.

Step-by-step explanation:

Speed is distance over time. Therefore, dividing distance by time will get you speed.

4 0

3 years ago

Read 2 more answers

Write an expression that represents the height of a tree that begins at 9 feet and increases by 3 feet per year. Let y represent

olga nikolaevna [1]

Answer:

h=3y+9

Step-by-step explanation:

We will write an expression using the y=mx+b format.

h in this case will be the height at any given year.

3 is the rate at which the three grows, y will represent any given year.

9 is the starting rate, or your y intercept.

4 0

3 years ago

Read 2 more answers

A box has colored balls (12 red, 10 green, 6 light blue and 8 yellow). What is the probability of drawing 2 red balls?

ale4655 [162]

Answer:

You will have a 33% chance of drawing a red ball

Step-by-step explanation:

If you do 12+10+8+6, you get 36 which then you would ratio it. 12:36, and you would convert that to a percent, which is 33%

7 0

3 years ago

2b^2x^2+3a^2y^2=a^2b^2 for b^2

Artemon [7]

Answer:

${b}^{2} = \frac{3 {a}^{2} {y}^{2} }{ {a}^{2} - 2 {x}^{2} }$

Step-by-step explanation:

We want to solve for b² in

$2 {b}^{2} {x}^{2} + 3 {a}^{2} {y}^{2} = {a}^{2} {b}^{2}$

Combine terms containing b²

$3 {a}^{2} {y}^{2} = {a}^{2} {b}^{2} - 2 {b}^{2} {x}^{2}$

Factor b² to get:

$3 {a}^{2} {y}^{2} = ({a}^{2} - 2 {x}^{2}) {b}^{2}$

Divide by a² -2b²

${b}^{2} = \frac{3 {a}^{2} {y}^{2} }{ {a}^{2} - 2 {x}^{2} }$

4 0

3 years ago