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Alisiya [41]
2 years ago
8

Help. Lol 6th grade math.

Mathematics
2 answers:
max2010maxim [7]2 years ago
6 0

Answer:

the first on  is howerd

number two is peter

Step-by-step explanation:

balu736 [363]2 years ago
5 0

Answer:

The first one is howard and the second one is peter

Step-by-step explanation:

Howard is at a higher elevation because he is above the sea level.

Peter is further from sea level because he is 1.1 meters away, whereas Howard is only 0.8 meters away.

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A certain ball is dropped from a height of x feet. It always bounces up to 2/3 x feet. Suppose the ball is dropped from 10 feet
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Given that if a ball is dropped from x feet, it bounces up to 2/3 x feet.

And the ball is dropped from 10 feet, that is x=10 feet,

So,before the first bounce it travels 10 feet distance.

Between first and second bounce it travels  \frac{2}{3}* 10 + \frac{2}{3} * 10 = 20*(\frac{2}{3})

Between second and third bounce, it travels 20*(\frac{2}{3})^{2}

Between third and fourth bounce, it travels 20*(\frac{2}{3}) ^{3}

Like that between 29th and 30th bounce, it travels 20*(\frac{2}{3} )^{29}

Hence total distance traveled is

    10+20*(\frac{2}{3} )+20*(\frac{2}{3})^{2} + 20*(\frac{2}{3}) ^{3}+......+20*(\frac{2}{3})^{29}

=10+20[(\frac{2}{3}) +(\frac{2}{3}) ^{2} +(\frac{2}{3}) ^{3} +.....+(\frac{2}{3} )^{29} ]

= 10+20[\frac{\frac{2}{3}*(1-(\frac{2}{3})^{29})  }{1-\frac{2}{3} }]

= 10+20*2*(1-(\frac{2}{3}) ^{29})

= 49.9997 feet ≈ 50 feet approximately.

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