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aleksley [76]
3 years ago
13

In the diagram,

Mathematics
1 answer:
forsale [732]3 years ago
4 0

Answer:

Probability that the measure of a segment is greater than 3 = 0.6

Step-by-step explanation:

From the given attachment,

AB ≅ BC, AC ≅ CD and AD = 12

Therefore, AC ≅ CD = \frac{1}{2}(\text{AD})

                                  = 6 units

Since AC ≅ CD

AB + BC ≅ CD

2(AB) = 6

AB = 3 units

Now we have measurements of the segments as,

AB = BC = 3 units

AC = CD = 6 units

AD = 12 units

Total number of segments = 5

Length of segments more than 3 = 3

Probability to pick a segment measuring greater than 3,

= \frac{\text{Total number of segments measuring greater than 3}}{Total number of segments}

= \frac{3}{5}

= 0.6

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