-5 x = 4 what property of equality was use to solve this equation
2 answers:
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for x = -2 → y = |-2| = 2 → (-2; 2)
for x = 0 → y = |0| = 0 → (0; 0)
for x = 2 → y = |2| = 2 → (2; 2)
Solve for x by cross multiplying then isolating the variable:
cross multiply
15x=90 Isolate the variable
x=6
Solve for y by cross multiplying then isolating the variable:
cross multiply
9y=90 Isolate the variable
y=10
15x=90 Isolate the variable
x=6
Solve for y by cross multiplying then isolating the variable:
9y=90 Isolate the variable
y=10