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2 years ago

5

What is the expanded form for 2.059

1 answer:

Artyom0805 [142]2 years ago

3 0

2+ 0.0+ 0.05+ 0.009okay so you just have to add the numbers. so you add 2+0.0+0.5+0.009. then you will get you answer. i hope this helps!!!!

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9. Khalid drove 66 miles on 3 gallons of gasoline. Which is the number of miles he could drive on 12 gallons of gasoline?

IrinaK [193]

Answer:

264 miles

Step-by-step explanation:

Find the unit rate (mpg):

66 miles

----------------- = 22 mpg

3 gallons

On 12 gallons he could drive (22 mpg)(12 gallons) = 264 miles

8 0

3 years ago

Just an answer and simple explanation! Thank you.

vazorg [7]

Answer:

15

Step-by-step explanation:

If CD and DE equal, then x+6 = 4x -21

So if you subtract x from both sides and plus 21 to both sides, that would be 3x = 27. Divide by 3 on both sides and you get 9.

Plug in x+6 with 9 and you get 15.

6 0

1 year ago

Help me please and thank you

sdas [7]

Answer:

Based on the model, the length of the wall is $\frac{9}{8}$ ft, the width of the wall is $\frac{1}{2}$ ft, and the height of the wall is $\frac{11}{8}$ ft. The volume of the portion of security wall that Tim has constructed so far is $\frac{99}{128}$ cu ft.

Step-by-step explanation:

Given:

The figure constructed shows a rectangular prism made up of small wooden cubes of length $\frac{1}{8}\ ft$ .

Width of the prism = $\frac{1}{2}\ ft$ .

To find length , height and volume of the figure.

Solution:

From the figure we can conclude that :

Length side of the prism counts 9 cubes.

Thus, length of the prism will be given as :

⇒ $\textrm{Length of each cube}\times \textrm{Number of cubes}$

⇒ $\frac{1}{8}\ ft\times 9$

⇒ $\frac{9}{8}\ ft$ (Answer)

Height side of the prism counts 11 cubes.

Thus, height of the prism will be given as :

⇒ $\textrm{Length of each cube}\times \textrm{Number of cubes}$

⇒ $\frac{1}{8}\ ft\times 11$

⇒ $\frac{11}{8}\ ft$ (Answer)

Volume of the prism can be given as :

⇒ $Length\times width\times height$

⇒ $\frac{9}{8}\ ft\times \frac{1}{2}\ ft\times \frac{11}{8}\ ft$

⇒ $\frac{99}{128}\ ft^3$ (Answer)

7 0

3 years ago

Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data

tresset_1 [31]

Based on the information represented by the boxplot ;

Latasha's lowest sale amount = 50

Kayla's median is between 200 and 300

Latasha has a greater spread due to higher IQR value

1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

The minimum value is denoted by the starting position of the lower whisker on a boxplot.

Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

50% of sales made by Kayla is between 200 and 300

With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

Q3 = 450 (Endpoint of the box)
Q1 = 150 (starting point of the box)

IQR = 450 - 150 = 300

<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

Q3 = 375 (Endpoint of the box)
Q1 = 100 (starting point of the box)
IQR = 375 - 100 = 275

Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

4 0

2 years ago

1 plus 1 equals something in a house! Can you answer??

Zarrin [17]

Answer:

horse horse horse horse

3 0

2 years ago