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just olya [345]
3 years ago
12

Which of the following represents the distance

Mathematics
1 answer:
Lunna [17]3 years ago
3 0

Answer:

D.  d = sqrt( ( x2-x1)^2 + (y2-y1)^2)

C.   d = sqrt( ( x1-x2)^2 + (y1-y2)^2)

B.  d = sqrt( (|x2-x1|^2 + |y2-y1|^2)

Step-by-step explanation:

Given two points (x1, y1) and (x2,y2)  we can find the distance using

d = sqrt( ( x2-x1)^2 + (y2-y1)^2)

The order of the terms inside the square doesn't matter

d = sqrt( ( x1-x2)^2 + (y1-y2)^2)

When we are squaring are term, we can take the absolute value before we square and it does not change the value

d = sqrt( (|x2-x1|^2 + |y2-y1|^2)

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Is the graph increasing decreasing or constant when y=2x
Simora [160]

Answer:

y=2 is increasing.

Step-by-step explanation:

y=2 means to move from (0,0) on the graph to (0,2). Since it is positive it is increasing. Idk if the x in y=2x changes the outcome or not. Hope this helps!

8 0
3 years ago
Three different ropes are used to pull boats in the water. Rope A is
Neko [114]

Answer:

I am pretty sure that it is a

5 0
3 years ago
What is the solution of 3+ X-2/x-3 less than or equal to 4
Archy [21]

Answer:

Step-by-step explanation:

3+3+\frac{x-2}{x-3} \leq 4\\\\\frac{x-2}{x-3} \leq 4-3\\\frac{x-3+1}{x-3} \leq 1\\1+\frac{1}{x-3} \leq 1\\\frac{1}{x-3} \leq 0\\x-3 \leq 0\\x\leq 3

5 0
3 years ago
Which statement is true? Question 12 options: A) |–3| = 3 and –|–4| = –4 B) |–3| = 3 and |–4| = –4 C) |–3| = 3 and –|4| = 4 D) –
alexandr402 [8]
A) |–3| = 3 and –|–4| = –4

It’s the only one that makes sense.

Hope that helps!
7 0
3 years ago
Determine the center and radius of the following circle equation:<br> x2 + y2 – 10x + 8y + 40 = 0
antiseptic1488 [7]

Answer:

The center of this circle is (5, -4) and the radius is 1.

Step-by-step explanation:

First regroup these terms according to x and y :

x^2 - 10x + y^2 + 8y = -40

Next, complete the square for x^2 - 10x:  x^2 - 10x + 5^2 - 5^2.

and the same for y^2 + 8y:  y^2 + 8y + 16 - 16

Substituting these results into x^2 - 10x + y^2 + 8y = -40, we get:

x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40.

Next, rewrite x^2 - 10x + 25 and y^2 + 8y + 16 as squares of binomials:

Then x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40 becomes:

(x - 5)^2 + (y + 4)^2 - 25 - 16 = -40, or:

(x - 5)^2 + (y + 4)^2 = 1

This equation has the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius.  Matching like terms, we get h = 5, k = -4 and r = 1.

The center of this circle is (5, -4) and the radius is 1.

6 0
3 years ago
Read 2 more answers
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