The only way to have two numbers that are the same and add up to be 15
is if they're both 7.5 , but those don't multiply to be 36. So I guess there's
no answer that satisfies all the conditions of this question.
Multiply first equaton by 2 and add to the other equation
6x+6y=12
<u>5x-6y=15 +</u>
11x+0y=27
11x=27
divide both sides by 11
x=27/11
sub back
3x+3y=6
divide both sides by 3
x+y=2
(27/11)+y=2
2 and 5/11+y=2
minus 2 and 5/11 both sides
y=-5/11
x=27/11
y=-5/11
(27/11,-5/11)
Answer:
-2
Step-by-step explanation:
Hey there!!
if we evaluate the expression it will look like :
3x + 14 = 8
and if we solve it:
3x+14=8
Step 1: Subtract 14 from both sides.
3x+14−14=8−14
3x=−6
Step 2: Divide both sides by 3.
3x/3 = -6/3
x= −2
- 5 + -3 = -8
hope this helps
when a negative number adds a negative number, it will be negative
when a negative number adds a positive number, whichever number (either positive or negative) take the sign of the bigger one
For example:
-4 + 3 = -1
-5 + 10 = 5
hope this helps
