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3 years ago

PLEASE HELP AS SOON AS POSSIBLE

Mathematics

2 answers:

Shalnov [3]3 years ago

5 0

Answer:

Picture is down below

Step-by-step explanation:

When you are doing this question you would just graph the points (-4,4) and (4,4) so we would get a width of 8 and you need an area of 8 so the height would just be 1 since the area of a rectangle is l times w. So when you graph it, it would look like this. And the coordinate points would be (-4,4), (4,4), (-4,3),(4,3).

Luda [366]3 years ago

3 0

Answer:

Answer is (-4,4), (4,4), (-4,3),(4,3).

Step-by-step explanation:

(-4,4), (4,4), (-4,3),(4,3).

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5(-1x+5)=10 pls help

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Answer:

-5x+5=10

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3 years ago

Find the missing angle measure, arc measure or solve for x. Show all<br> work!

n200080 [17]

Answer:

mYW = 151°

Step-by-step explanation:

∠XWY is an inscribed angle because it has a vertex on the circle. This means that m∠XWY is half of the arc it intercepts, which is XY. We can model the situation using an equation:

m∠XWY = mXY / 2

37° = mXY / 2

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All arcs in a circle add up to 360°. Because of this, we can say:

mXY + mYW + mWX = 360°

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3 years ago

If f(x)= -6x+6 then f^-1(x)=

drek231 [11]

Recall that, to get the inverse relation of any expression, we start off by doing a quick switcharoo on the variables, then we solve for "y".

$\bf \stackrel{f(x)}{y}=-6x+6\qquad inverse\implies \boxed{x}=-6\boxed{y}+6
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3 years ago

Given the vectors A⃗ and B⃗ shown in the figure ((Figure 1) ), determine the magnitude of B⃗ −A⃗. A is 28 degrees above the posi

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This problem is represented in the Figure below. So, we can find the components of each vector as follows:

$\bullet \ cos(28^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{A_{x}}{44} \\ \\ \therefore A_{x}=44cos(28^{\circ})=38.85m \\ \\ \\ \bullet \ sin(28^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{A_{y}}{44} \\ \\ \therefore A_{y}=44sin(28^{\circ})=20.65m$

$\bullet \ cos(56^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{-B_{x}}{26.5} \\ \\ \therefore B_{x}=-26.5cos(56^{\circ})=-14.81m \\ \\ \\ \bullet \ sin(56^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{B_{y}}{26.5} \\ \\ \therefore B_{y}=26.5sin(56^{\circ})=21.97m$

Therefore:

$\vec{A}=(38.85, 20.65)m \\ \\ \vec{B}=(-14.81, 21.97)m$

So:

$\vec{B}-\vec{A}=(-14.81, 21.97)-(38.85, 20.65)=(-53.66,1.32)$

Finally, the magnitude is:

$\boxed{\left| \vec{B}-\vec{A}\right|=\sqrt{(-53.66)^2+(1.32)^2}=53.67m}$

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