Answer:
120000000
Step-by-step explanation:
The inequality that represents the range of k so that inequality 1 has real solution is -3 < k < 5
<h3>How to determine the range?</h3>
<u>Inequality 1</u>
x^2 + (k + 1)x + k + 4 > 0
The discriminant is calculated using
D = b^2 - 4ac
So, we have:
D = (k + 1)^2 - 4 * 1 * (k + 4)
Evaluate
D = k^2 + 2k + 1 - 4k - 16
This gives
D = k^2- 2k - 15
Factorize the equation
D = (k+ 3)(k -5)
Solve for k
k = -3 and k = 5
Express the k values as inequalities
-3 < k < 5
<u>Inequality 2</u>
The inequality cannot be read, because of the image quality
Read more about discriminant at:
brainly.com/question/7784687
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You just multiply 3 by both 15x and -17. None of these choices are correct. The only correct application would be A.
Answer:
4(xy + 3w + 3z)
Step-by-step explanation:
The GCF is 4, so you can take that out and put it in front of the parentheses. Then you just divide all of the terms by 4 (4xy / 4 = xy; 12w / 4 = 3w; 12z / 4 = 3z), etc.
Answer:
Factor form of the equation makes it easiest to see the zeros of the function.
Step-by-step explanation:
f(x)=(x−4)(x−6), because you can see when each factor is equal to zero.
Just equate the factor with zero and you will get its zeros.
f(x)=(x−4)(x−6)
Let f(x)= 0
Therefore
(x−4)(x−6) = 0
Therefore
(x−4) = or (x−6)= 0
Therefore, x = 4 or x = 6
Hence, 4 and 6 are the zeros of the given function.
