an object begins at x=75.2m and undergoes a displacement of -48.7m. what is its final displacement(unit m)
2 answers:
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Answer:
A sample of is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is of:
In a previous study of 1012 randomly chosen respondents, 374 said that there should be such a law.
This means that
95% confidence level
So , z is the value of Z that has a pvalue of
, so
.
How large a sample size is needed to be 95% confident with a margin of error of E?
A sample size of n is needed, and n is found when M = E.
A sample of is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.
Answer:
The number of seat when n is odd
The number of seat when n is even
Step-by-step explanation:
Given that, each successive row contains two fewer seats than the preceding row.
Formula:
The sum n terms of an A.P series is
a = first term of the series.
d= common difference.
n= number of term
l= last term
term of a A.P series is
n is odd:
n,n-2,n-4,........,5,3,1
Or we can write 1,3,5,.....,n-4,n-2,n
Here a= 1 and d = second term- first term = 3-1=2
Let of the series is n.
Here , n=t, a=1 and d=2
⇒(t-1)2=n-1
Last term l= n,, the number of term , First term = 1
Total number of seat
n is even:
n,n-2,n-4,.......,4,2
Or we can write
2,4,.......,n-4,n-2,n
Here a= 2 and d = second term- first term = 4-2=2
Let of the series is n.
Here , n=t, a=2 and d=2
⇒(t-1)2=n-2
Last term l= n, the number of term , First term = 2
Total number of seat