This is a way to work it out
Answer:
the function is continuous from the left at x=1 and continuous from the right at x=0
Step-by-step explanation:
a function is continuous from the right , when
when x→a⁺ lim f(x)=f(a)
and from the left when
when x→a⁻ lim f(x)=f(a)
then since the functions presented are continuous , we have to look for discontinuities only when the functions change
for x=0
when x→0⁺ lim f(x)=lim e^x = e^0 = 1
when x→0⁻ lim f(x)=lim (x+4) = (0+4) = 4
then since f(0) = e^0=1 , the function is continuous from the right at x=0
for x=1
when x→1⁺ lim f(x)=lim (8-x) = (8-0) = 8
when x→1⁻ lim f(x)=lim e^x = e^1 = e
then since f(1) = e^1=e , the function is continuous from the left at x=1
Answer:
3(x + 1) + 6 = 33
3x+3+6=33
3x+9=33
3x=33-9
3x=24
x=24/3
x=8
Step-by-step explanation:
hope it help ^_^
Answer:
This picture shows you what the equation would look like on a graph.
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
x and x are same terms.
