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AveGali [126]
3 years ago
10

4.

Biology
1 answer:
yaroslaw [1]3 years ago
8 0

The question is incomplete as it does not have the option which are:

  • Favorable genes from parental generations provide advantageous characteristics to the hybrid species.
  • Hybridization produces offspring traits that allow different species to survive in extreme environments.
  • Inherited traits passed on from parental generations make hybrid species more susceptible to disease.
  • Hybrid species display more adaptation due to their reduced genetic diversity

Answer:

Favorable genes from parental generations provide advantageous characteristics to the hybrid species.

Explanation:

The white cattail is the plants which grow in the wetlands that are they are adapted to grow in the wetlands. The white cattail species in nature is the result of natural hybridization that is mixing of the genes of two different species of the same genus.

The white cattail can when grown in the Midwestern states well adapted to grow in that area and the reason for this could be accounted that the genes from the parental plants provided many advantages to the newly formed hybrid species.

Thus, the selected option is correct.

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5 0
2 years ago
The curly toe phenotype is controlled by 4 genes that act in an additive manner. The environment does not have an effect on this
Sergio [31]

Answer:

  1. What is the highest number of risk units an individual can have with this model? 48 units of risk
  2. What is the phenotype of an individual of genotype AaBbCCDd? The individual has curly toes
  3. Is it possible for them to have a child with curly toes?

        Yes, the couple can have children with curly toes.

Explanation:

<u>Available data</u>:

  • The curly toe phenotype is controlled by 4 diallelic additive genes
  • Genes A, B, C, D  
  • A dominant allele has 6 units of risk
  • A recessive allele has 2 units of risk
  • Individuals with more than 35 units of risk have curly toes
  • Individuals with 35 or fewer risk units have straight toes

The term quantitative heritability refers to the transmission of a phenotypic trait in which expression depends on the additive effect of a series of genes.  

Polygenic heritability occurs when a trait results from the interaction of more than one gene. And these genes can also have more than two alleles. The action of many genes and alleles can cause many different combinations that are the reason for genotypic graduation.  

Quantitative traits are those that can be measure, such as longitude, weight, eggs laid per female, among others. These characters do not group individuals by any precise and clear categories. Instead, they group individuals in many different categories that depend on how the genes were intercrossed and distributed during meiosis. The result depends on the magnitude in which each allele contributes to the final phenotype and genotype. When they interact, they create a gradation in phenotypes, according to the level of contribution.

According to this information, and knowing how each allele contributes to the risk, we can say that the minimum units of risk are 16, determined by the recessive genotype aabbccdd. Each recessive allele contributes with 2 units of risk, so (aa=4units + bb=4 units + cc=4 units + dd=4 units) =  16 units.

Each time a dominant allele is present in the genotype, it adds 6 units to the total risk.    

What is the highest number of risk units an individual can have with this model?

48 units of risk, which corresponds to the genotype AABBCCDD. Each dominant allele contributes 6 units to the risk. There are 8 dominant alleles, so, 8x6=48 units.

What is the phenotype of an individual of genotype AaBbCCDd?

The individual has curly toes because it has a risk of 36 units, which is superior to the limit of 35 units. Dominant alleles A, B, C, C, D contribute with 30 units of risk (6x5), and recessive alleles a, b, d contribute 6 units of risk (3x2).

Cross:

Parentals) AAbbCcDd   x   AaBbCCDd

Gametes) AbCD, AbcD, AbCd, Abcd

               ABCD, ABCd, AbCD, AbCd, aBCD, aBCd, abCD, abCd

Punnett square)  AbCD                 AbcD               AbCd               Abcd

          ABCD    AABbCCDD     AABbCcDD     AABbCCDd     AABbCcDd

          ABCd    AABbCCDd      AABbCcDd     AABbCCdd      AABbCcdd

          AbCD    AAbbCCDD      AAbbCcDD    AAbbCCDd     AAbbCcDd

         AbCd     AAbbCCDd       AAbbCcDd     AAbbCCdd     AAbbCcdd

         aBCD     AaBbCCDD      AaBbCcDD      AaBbCCDd     AaBbCcDd

         aBCd     AaBbCCDd      AaBbCcDd      AaBbCCdd     AaBbCcdd

         abCD     AabbCCDD      AabbCcDD      AabbCCDd    AabbCcDd

         abCd      AabbCCDd      AabbCcDd      AabbCCdd        AabbCcdd

F1) 16 /32 = 1/2 individuals in the progeny are expected to have curly toes

     16 /32 = 1/2 individuals are expected to have straight toes

Is it possible for them to have a child with curly toes?

Yes, the couple can have children with curly toes.

To have curly toes, individuals must have more than 35 units of risk.

To have more than 35 units, individuals´ genotypes must carry at least 5 dominant alleles (which equal 30 units).

8 0
3 years ago
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