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navik [9.2K]
4 years ago
15

8) -7x – 2y = -13 x– 2y = 11​

Mathematics
1 answer:
ryzh [129]4 years ago
3 0

02827=298282726/[email protected]^×^7

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Lucero has two identical normal distributions, but new data has just arrived, and now she is going to have to add 6 values to on
Anettt [7]

Answer:

a. it will have more spread

for prepworks users :)

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Which postulate or theorem could be used to prove triangleLMQ is congruent to triangleLNP
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I believe the correct answer is B. :)
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Which equation is represented by the graph below?
cluponka [151]

Answer: 2/3 x +6

Step-by-step explanation:

slope is 2/3 and y intercept is 6

7 0
3 years ago
X ^ (2) y '' - 7xy '+ 16y = 0, y1 = x ^ 4
nignag [31]
Standard reduction of order procedure: suppose there is a second solution of the form y_2(x)=v(x)y_1(x), which has derivatives

y_2=vx^4
{y_2}'=v'x^4+4vx^3
{y_2}''=v''x^4+8v'x^3+12vx^2

Substitute these terms into the ODE:

x^2(v''x^4+8v'x^3+12vx^2)-7x(v'x^4+4vx^3)+16vx^4=0
v''x^6+8v'x^5+12vx^4-7v'x^5-28vx^4+16vx^4=0
v''x^6+v'x^5=0

and replacing v'=w, we have an ODE linear in w:

w'x^6+wx^5=0

Divide both sides by x^5, giving

w'x+w=0

and noting that the left hand side is a derivative of a product, namely

\dfrac{\mathrm d}{\mathrm dx}[wx]=0

we can then integrate both sides to obtain

wx=C_1
w=\dfrac{C_1}x

Solve for v:

v'=\dfrac{C_1}x
v=C_1\ln|x|+C_2

Now

y=C_1x^4\ln|x|+C_2x^4

where the second term is already accounted for by y_1, which means y_2=x^4\ln x, and the above is the general solution for the ODE.
4 0
3 years ago
A monument in a park is shaped like a square pyramid. The dimensions are shown in the net. What is the surface area of the monum
vampirchik [111]

The surface area of the monument shaped like a square pyramid is 14 m².

<h3>Area </h3>

Area is the amount of space that is occupied by a two dimensional shape or object.

From the diagram

Area of each triangle = (1/2) * base * height = (1/2) * 2 * 2.5 = 2.5 m²

Area of square = length * length = 2 m * 2 m = 4 m²

Surface area of monument = 4(2.5) + 4 = 14 m²

The surface area of the monument shaped like a square pyramid is 14 m².

Find out more on Area at: brainly.com/question/25292087

5 0
3 years ago
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