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3 years ago

Which postulate or theorem could be used to prove triangleLMQ is congruent to triangleLNP

Mathematics

2 answers:

Tpy6a [65]3 years ago

8 0

AA because you can only prove a triangle is similar if the angle measurements are the same since the side sizes making it similar and not congruent.

Cerrena [4.2K]3 years ago

7 0

I believe the correct answer is B. :)

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If we apply the Pythagorean Theorem to the Egyptian knots we can see that 3^2 + 4^2 = 5^23 2 +4 2 =5 2 . Which of the sets of th

pantera1 [17]

Answer:

B) { 51, 149, 140 }

C) { 16, 63, 65 }

Step-by-step explanation:

We need to choose Pythagoras theorem formula

$c^2=a^2+b^2$

now, we can verify each options

option-A:

a=1

b=1

c=1

now, we can verify formula

$1^2=1^2+1^2$

$1=2$

We can see that left side is not equal to right side

so, this is FALSE

option-B

a=51

b=140

c=149

now, we can verify formula

$149^2=51^2+140^2$

$22201=22201$

We can see that left side is equal to right side

so, this is TRUE

option-C

a=16

b=63

c=65

now, we can verify formula

$65^2=16^2+63^2$

$4225=4225$

We can see that left side is equal to right side

so, this is TRUE

option-D:

a=6

b=8

c=11

now, we can verify formula

$11^2=6^2+8^2$

$121=100$

We can see that left side is not equal to right side

so, this is FALSE

3 0

3 years ago

Read 2 more answers

Plz guys help me plz

goldenfox [79]

It’s hard to see! Please let me know the numbers on the graph

6 0

3 years ago

Luis has three than dimes in his pocket, for a total of 1.80. which equation could be used to determine the number of dimes

Oksi-84 [34.3K]

X= 1.80/10 . x is the number of dimes. 1.80 is your total and 10 represents the worth of the dime

4 0

3 years ago

I need the answer ASAP

3241004551 [841]

Answer:

Hey there!

The answer is 2 1/4, which is 2.25

Let me know if you have any other questions!

5 0

3 years ago

Read 2 more answers

I NEED HELP PLEASE ASAP !

In-s [12.5K]

The first rule you need to know is

$(a^b)^c=a^{bc}$

So, you have

$\dfrac{(x^{25})^{-6}}{(x^{-3})^{48}}=\dfrac{x^{25\cdot(-6)}}{x^{-3\cdot 48}}=\dfrac{x^{-150}}{x^{-144}}$

The second rule you need to know is

$\dfrac{a^b}{a^c}=a^{b-c}$

So, you have

$\dfrac{x^{-150}}{x^{-144}}=x^{-150-(-144)}=x^{-150+144}=x^{-6}$

4 0

3 years ago

Read 2 more answers