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Katena32 [7]
3 years ago
15

Sec^2x-1/sec^2x=sin^2x

Mathematics
1 answer:
disa [49]3 years ago
7 0
\dfrac{\sec^2x-1}{\sec^2x}=1-\dfrac1{\sec^2x}=1-\cos^2x=\sin^2x
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