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Katena32 [7]
3 years ago
15

Sec^2x-1/sec^2x=sin^2x

Mathematics
1 answer:
disa [49]3 years ago
7 0
\dfrac{\sec^2x-1}{\sec^2x}=1-\dfrac1{\sec^2x}=1-\cos^2x=\sin^2x
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A coordinate plane with the x-axis labeled Blueberries (in pints) and the y-axis labeled Cost (in dollars) shows a line going through (0, 0) and (5, 17).

<h3>What is directly proportional?</h3>

It is defined as the relationship between two quantities as one quantity increases the other quantity also increases and vice versa.

It is given that there is a proportional relationship between cost and pints of blueberries as,

Blueberries (in pints)          2      5

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17/6.80 = 5/2

As we draw the graph and analyze each option one by one we get the graph shown by the statement C following the given proportional relationship.

Thus, a coordinate plane with the x-axis labeled Blueberries (in pints) and the y-axis labeled Cost (in dollars) shows a line going through (0, 0) and (5, 17).

Learn more about the directly proportional here:

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