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antoniya [11.8K]
3 years ago
14

HELP ME ASAPHelp me solve this so I can understand it more..plz show me work

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
5 0

Answer:

The question is not fully visible but what u want to do is group them subtract/add what u can and then factor it out

Step-by-step explanation:

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The asymptote of the function f(x) = 3x + 4 is y = _____.
raketka [301]
I would say y equals 3x.
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What is 36ft=------yd
posledela
If you are asking how may yards are in 36 feet, I can help you on this!

There are 3 feet in a yard, so to find this out, you need to divide 36 by 3.
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3 years ago
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Help me asap! I will give you marks
Law Incorporation [45]

Recall the binomial theorem.

(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k

1. The binomial expansion of \left(1+\frac x3\right)^7 is

\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}

Observe that

k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x

k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2

When we multiply these by 8-9x,

• 8 and \frac73 x^2 combine to make \frac{56}3 x^2

• -9x and \frac73 x combine to make -\frac{63}3 x^2 = -21x^2

and the sum of these terms is

\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}

2. The binomial expansion is

\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k

We get the a^6b^2 term when k=2 :

k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2

6 0
1 year ago
Simplify 10(N + 3).<br><br> 10N + 30<br> 10N + 13<br> 10N + 3
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10(N + 3)

= 10N + 30

Hence, the answer is A.
3 0
3 years ago
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Plzzz help i will give brainliest if i can
Alla [95]

Answers: choice C and choice E

Plugging x = 3 and y = -1 into both equations of choice C lead to a true result (the same number on both sides). This is why the system of equations listed in choice C is one possible answer. Choice E is a similar story.

If your teacher didn't mean to make this a "select all that apply" type of problem, then it's likely your teacher may have made a typo.

3 0
2 years ago
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