When we are given a system of 3 linear equations, with 3 variables, we proceed as follows:
We consider 2 pairs or equations, for example (1, 2) and (2, 3), and eliminate one of the variables in each pair, creating a system of 2 linear equations with 2 unknowns.
Note that the third equation contains -2y which can be used to eliminate easily -6y in the second equation, and -4y in the fourth.
i) consider equations 1 and 3:
-3x-4y-3z=-7
5x-2y+5z=9
multiply the second equation by -2:
-3x-4y-3z=-7
-10x+4y-10z=-18
adding the 2 equations we have -13x-13z=-25
ii) consider equations 2 and 3. Multiply the third equation by -3:
2x-6y+2z=3
-15x+6y-15z=-27
adding the 2 equations we have -13x-13z=-24
So we got -13x-13z is -25, but also -24. this means the system is inconsistent, so it has no solution.
Answer: the system has no solutions
Answer:
D
Step-by-step explanation:
When taking an esponent to an exponent multiply them
4 ^(1/3)^3 = 4^1 = 4
I am assuming the angle is given in degrees.
Answer:
12.71
or in terms of Pi
182π / 45
Steps:
Formula for the arc length:
L = 2πr(θ/360)
We are given r and θ. Let’s solve for L.
L = 2* π * 8 * (92/360)
The answer is 12.71
or in terms of Pi
182π / 45
There was 3 erasers in each pack because 2 times 3 is 6 plus 2 equals 8. so there are 3 in each pack.
Answer:
21.56
Step-by-step explanation:
