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Lostsunrise [7]
3 years ago
15

Nelson finds a video game for $38.50.  The game is on sale for $31.57.  What is the percent of discount on the game?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
8 0
38.50 = 100%
31.57 = ?

Multiply: 31.57 x 100 = 3,157

Divide: 3,157 ÷ 38.50 = 82%
100-82= 18% discount
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HELP WITH THESE 3 QUESTIONS (BRIANLIEST AND 50 POINTS) hint: question 1 is answered (NO LINKS)
Rasek [7]

Answer:

45 points in round 3

Step-by-step explanation:

x + 30 + 25 = 100

combine like terms

30+25 = 55

x + 55 = 100

  - 55     - 55

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x = 45

therefore, Amos scored 45 points in round 3

hope this helps! :D

have a MIRACULOUS day, and brainliest is immensely appreciated!! <3

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2 years ago
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What is the overhead of a pharmacy in a year that it pays $474,900 in salaries, $24,000 in rental fees, $31,505 for utilities, $
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4 years ago
A restaurant sells burritos for $8.00 each. The cost of the meat is $1.50 and the cost of the other ingredients is $1.00 for eac
ollegr [7]

Answer:

Profit for 100 burritos: $550

Cost to make one burrito: $2.50

Step-by-step explanation:

If a restaurant sells burritos for $8, that's a positive 8 dollars they earned. Then, we need to find what the cost was to make the burrito. If the meat is 1.50 and the cost for all the other ingredients is 1 dollar, then they lose 2.50 for every 8 dollars they make (for each burrito). So, to find the profit in one burrito, we would add -2.5+8, giving us an answer of 5.5. So, they earn 5 dollars and 50 cents each burrito and lose $2.50.

Now, we need to find the profit of 100 burritos

If one burrito is $5.50 in profit, then we take that amount and multiply it by 100. This is to make the illitsratution of selling 100 burritos. So, 5.50*100 would be 550! They would make $550 for 100 burritos, and lose 250 dollars on all of the burrito ingredients.  

6 0
2 years ago
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Will Name Brainliest!!!!!!! :)
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A' (0,4) respuesta es

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3 years ago
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Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the
Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

y=Ce^{kt}. We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is \frac{dy}{dt}. Thus, the change in the concentration of salt is found in

\frac{dy}{dt}= inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

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-\frac{3t}{400}

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