What is the area, in square units, of the trapezoid?

Mathematics

1 answer:

Misha Larkins [42]3 years ago

6 0

Answer:

Step-by-step explanation:

plzmark brainliest

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What is the sum of 52 and its additive inverse?

Lisa [10]

Hello there!

The additive inverse of any number just means to flip it's value.

For example;

The number "3" would have an additive inverse of "-3".
The number "-15" would have an additive inverse of "15".

Since we have "52", we can flip the value sign of it.
We now have -52 and 52.

Since the question asked us to sum our numbers, we need to add them.

-52 + 52 = 0

The sum of 52 and its additive inverse is 0.

I hope this helps!

5 0

3 years ago

Fiona has to choose a bouquet for her wedding. The probability that she uses red roses is 98%, the probability that she uses orc

tekilochka [14]

0.84: you would do .82/.98 (the probability of orchids and roses divided by probability of roses)

7 0

3 years ago

-4x+y=3 plzz answerrr simplify itt

geniusboy [140]

Answer:

x= -3/4 + y/4

Step-by-step explanation:

Move all terms that don't contain

x to the right side and solve.

3 0

3 years ago

Lewis fills his thermos with 2 liter of water. Garret fill his thermos with 1 of water. How many more milliliter of water does l

cluponka [151]

For this case we have to:

Lewis carries 2 liters of water

Garret carries 1 liter of water

So, Lewis has 1 liter of water more than Garret.

By definition we have that 1 liter equals 1000 milliliters.

Thus, Lewis carries 1000 milliliters more water than Garret.

Answer:

1000 milliliters

7 0

3 years ago

Write the equation of a hyperbola with vertices (0, -4) and (0, 4) and foci (0, -5) and (0, 5).

andre [41]

Check the picture below. So, more or less looks like so.

notice, the center is clearly at the origin, and notice how long the "a" component is, also, bear in mind that, is opening towards the y-axis, that means the fraction with the "y" variable is the positive one.

Also notice, the "c" distance from the center to either foci, is just 5 units.

$\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{{{ a }}^2+{{ b }}^2}
\end{cases}\\\\
-------------------------------\\\\$

$\bf \begin{cases}
h=0\\
k=0\\
a=4\\
c=5
\end{cases}\implies \cfrac{(y-{{ 0}})^2}{{{ 4}}^2}-\cfrac{(x-{{ 0}})^2}{{{ b}}^2}=1\implies \cfrac{y^2}{16}-\cfrac{x^2}{b^2}=1
\\\\\\
c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\\\\\\
\sqrt{5^2-4^2}=b\implies \boxed{3=b}
\\\\\\
\cfrac{y^2}{16}-\cfrac{x^2}{3^2}=1\implies \boxed{\cfrac{y^2}{16}-\cfrac{x^2}{9}=1}$

7 0

3 years ago