What is the area, in square units, of the trapezoid?

Mathematics

1 answer:

Misha Larkins [42]3 years ago

6 0

Answer:

Step-by-step explanation:

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Is a measure of 26 inches "far away" from a mean of 16 inches? As someone with knowledge of statistics, you answer "it depen

alexandr402 [8]

Answer: Hello!

In a normal distribution, between the mean and the mean plus the standar deviation, there is a 34.1% of the data set, between the mean plus the standar deviation, and the mean between two times the standard deviation, there is a 16.2% of the data set, and so on.

If our mean is 16 inches, and the measure is 26 inches, then the difference is 10 inches between them.

a) if the standar deviation is 2 inches, then you are 10/2 = 5 standar deviations from the mean.

b) yes, is really far away from the mean, in a normal distribution a displacement of 5 standar deviations has a very small probability.

c) Now the standar deviation is 7, so now 26 is in the range between 1 standar deviation and 2 standar deviations away from the mean.

Then this you have a 16% of the data, then in this case, 26 inches is not far away from the mean.

3 0

3 years ago

Pls answer precisely

Nata [24]

Answer:

The third one

Step-by-step explanation:

Its asking if its positive in the interval [-3, -2]

Which means you only look at the graph from -3, -2 on the x axis and we are looking see which one is positive in that space. And by positive it means going up in a positive direction. Only the third one does this.

3 0

3 years ago

A sphere has a radius of 16 in. Which statements about the sphere are true? Check all that apply.

Wewaii [24]

Answer:

The sphere has a diameter of 32 in. CORRECT: the diameter of a sphere doubles its radio, so if the radio equals 16,the diameter measures the double, in this case, 32.
The radius' lenght is one half the length of the diameter. CORRECT: , by definition, the diameter is the maximum distance between two opposite points on the surface of the sphere, and its lenght equals twice the radius because the radius is the distance between the center of the sphere and any point of the frontier of the sphere (then, one colud imagine that the distance between two opposite points in a sphere can be united by two radius, or a diameter).
The volume (V) of a sphere can be calculated as $\frac{4\pi r^3}{3}$ , where r is the radio. In this case, the volume of the sphere will be $\frac{4\pi\times16^3}{3}=\frac{4\pi\times4096}{3}$ , which is also equal to $\frac{16384\times\pi}{3}$ .