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4 years ago

What is the radical expression that is equivalent.

Mathematics

1 answer:

grandymaker [24]4 years ago

7 0

Answer:

$27^{\frac{1}{5}} = \sqrt[5]{27}$

Step-by-step explanation:

Rule of exponents:

$a^{\frac{1}{n}} = \sqrt[n]{a}$

Apply the rule to this case:

$27^{\frac{1}{5}} = \sqrt[5]{27}$

You might be interested in

Use the cross products property to solve the proportion 10/7 equals 8 / K what does k equal

Ivanshal [37]

Answer:

5.600

Step-by-step explanation:

5 0

3 years ago

Add the following<br> -5+(-7)+9+(-3)<br> - 5+(-7)+9+(-3)=(Simplify your answer.)

IceJOKER [234]

Answer:

-5+(-7)+9+(-3) = -6

Step-by-step explanation:

We need to add the following i.e.

-5+(-7)+9+(-3)

We know that, +(-) = - (minus)

So,

-5-7+9-3 = -12+6

= -6

So, the value of the given expression is equal to -6.

7 0

3 years ago

Evaluate the expression when a=-15 and b=-5. b^2 / a + 5

DENIUS [597]

Answer: 20/3

Solution:

-5^2/-15 + 5
Determine the sign

5^2/15 + 5
Calculate

25/15 + 5
Simplify

5/3 + 5
Transform the expression

5 + 15/3
Calculate

= 20/3

(But there’s alternative forms too!: 6.6, 6 2/3)

3 0

2 years ago

joe worked 8days for a total of 58.4hours. If he worked the same number of hours each day, how many hours did he work in a day?

Maru [420]

Answer:

7.3 hours per day.

Step-by-step explanation:

Just do 58.4 divided by 8 and you get 7.3.

*Hope this helps*

5 0

3 years ago

What is the simplified form of the following expression? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0 2

finlep [7]

To solve such questions we need to know more about expression.

<h2 /><h2>Expression </h2>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations that are formed according to rules which are dependent on the context.

<h2 /><h2 /><h2>Given to us,</h2>

$2\sqrt[4]{16x}-2\sqrt[4]{2y}+3\sqrt[4]{81x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-16\sqrt[4]{2y}+13\sqrt[4]{4}-10\sqrt[4]{2y}+35\sqrt[4]{x}-18\sqrt[4]{2y}$

rearranging we get,

$=2\sqrt[4]{16x}+3\sqrt[4]{81x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{4}+35\sqrt[4]{x}-2\sqrt[4]{2y}-4\sqrt[4]{32y}-4\sqrt[4]{32y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$

we know that,

$\sqrt[4]{81}=3\\\sqrt[4]{16}=2\\\sqrt[4]{32}=2\sqrt[4]{2}\\$

therefore,

$=4\sqrt[4]{x}+9\sqrt[4]{x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{x}+35\sqrt[4]{x}-2\sqrt[4]{2y}-8\sqrt[4]{2y}-8\sqrt[4]{2y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$