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Fudgin [204]
3 years ago
10

How would you get 50% of the vitamin c

Mathematics
1 answer:
Eva8 [605]3 years ago
5 0

No context....... please add some context

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Translate into an Algebraic equation: The quotient of a number and 5
gavmur [86]

\rule{300}{1}\\\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}

<em>Translate into an algebraic equation:-</em>

<em>The quotient of a number and 5.</em>

<em />

<em />\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}

✳︎ First, the word "quotient" indicates that we divide.

Here, we have the quotient of a number and 5, so we divide the number by 5; let the number be d.

So the quotient of d and 5 looks as follows:-

\bold{\dfrac{f}{5}}

<h3>Good luck with your studies.</h3>

\rule{300}{1}

8 0
2 years ago
Help me please everyone;-;
Debora [2.8K]

Answer:

x - 4

Step-by-step explanation:

\sf \bigg( \dfrac{ {x}^{4} }{ {x}^{3} }  \bigg) - 4

\sf \bull \dfrac{{a}^{m} }{ {a}^{n} }  =  {a}^{m - n}

\sf \:  {x}^{4 - 3}  - 4

\sf{x}^{1}  - 4

\sf \: x - 4

4 0
2 years ago
Read 2 more answers
Which of the following statements about the picture is true
Contact [7]

Answer:

  (c)  Point A is not on a bisector

Step-by-step explanation:

The figure shows you AR > AT. Since AX is the same for both triangles, angle AXR must be greater than angle AXT. This means AX is not the bisector of angle X.

Since AT is perpendicular to XT, it cannot be the perpendicular bisector of XT. That bisector will intersect XT at its midpoint, not its end.

The marked distances show you that A is different distances from T and R.

The only statement that makes any sense is ...

  Point A is not on a bisector.

7 0
2 years ago
The residual value in a car lease agreement is what the leasing company believes the car will be worth at the end of your lease.
jok3333 [9.3K]

Answer:

$10,560

Step-by-step explanation:

48% of $22,000 is $10,560

3 0
3 years ago
I need help please.
GuDViN [60]

Answer:

The factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....

Step-by-step explanation:

The given expression is:

2q²-5pq-2q+5p

Make a pair of first two terms and last two terms:

(2q²-5pq) - (2q-5p)

Now factor out the common factor from each group.

Note that there is no common factor in second group. So we will take 1 as a common factor.

q(2q-5p) -1(2q-5p)

Now factor the polynomial by factoring out the G.C.F, 2q-5p

(2q-5p) (q-1)

Thus the factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....

4 0
3 years ago
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