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Rama09 [41]
2 years ago
6

What is the simplified form of the following expression? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0 2

(RootIndex 4 StartRoot 16 x EndRoot) minus 2 (RootIndex 4 StartRoot 2 y EndRoot) 3 (RootIndex 4 StartRoot 81 x EndRoot) minus 4 (RootIndex 4 StartRoot 32 y EndRoot) 5 (RootIndex 4 StartRoot x EndRoot) minus 4 (RootIndex 4 StartRoot 32 y EndRoot) 5 (RootIndex 4 StartRoot x EndRoot) minus 6 (RootIndex 4 StartRoot 2 y EndRoot) 13 (RootIndex 4 StartRoot x EndRoot) minus 10 (RootIndex 4 StartRoot 2 y EndRoot) 35 (RootIndex 4 StartRoot x EndRoot) minus 18 (RootIndex 4 StartRoot 2 y EndRoot).
Mathematics
2 answers:
finlep [7]2 years ago
7 0

To solve such questions we need to know more about expression.

<h2 /><h2>Expression </h2>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations that are formed according to rules which are dependent on the context.  

<h2 /><h2 /><h2>Given to us,</h2>

2\sqrt[4]{16x}-2\sqrt[4]{2y}+3\sqrt[4]{81x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-16\sqrt[4]{2y}+13\sqrt[4]{4}-10\sqrt[4]{2y}+35\sqrt[4]{x}-18\sqrt[4]{2y}

rearranging we get,

=2\sqrt[4]{16x}+3\sqrt[4]{81x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{4}+35\sqrt[4]{x}-2\sqrt[4]{2y}-4\sqrt[4]{32y}-4\sqrt[4]{32y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}

we know that,

\sqrt[4]{81}=3\\\sqrt[4]{16}=2\\\sqrt[4]{32}=2\sqrt[4]{2}\\

therefore,

=4\sqrt[4]{x}+9\sqrt[4]{x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{x}+35\sqrt[4]{x}-2\sqrt[4]{2y}-8\sqrt[4]{2y}-8\sqrt[4]{2y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}

taking \sqrt[4]{x} and \sqrt[4]{2y} as common

=[(\sqrt[4]{x})(4+9+5+5+13+35)]-[(2+8+8+16+10+18)(\sqrt[4]{2y})]

Further simplifying

=71\sqrt[4]{x}-62\sqrt[4]{2y}

Learn more about the expression:

brainly.com/question/13947055?referrer=searchResults

RUDIKE [14]2 years ago
7 0

Answer:

Keep it simple: C

Step-by-step explanation:

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Answer:

Mean =\sum x P(x) = 36.86

Standard deviation =\sum x^2P(X)=1360.9

Step-by-step explanation:

x          P(x) x \times P(x)       x^2 \times  P(x)

33         0.02     0.66          21.78

34          0.06     2.04         69.36

35           0.1      3.5        122.5

36           0.2      7.2         259.2

37           0.24     8.88        328.56

38           0.26     9.88        375.44

39            0.1     3.9         152.1

40            0.02     0.8         32

             1        36.86      1360.9

We are supposed to find mean and standard deviation

Mean =\sum x P(x) = 36.86

Standard deviation =\sum x^2P(X)=1360.9

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