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3 years ago

I need help anybody ?

Mathematics

1 answer:

nasty-shy [4]3 years ago

6 0

Answer and Step-by-step explanation:

Simply use the Pythagorean Theorem to solve.

The Pythagorean Theorem is used to solve for a side in right triangles.

$A^{2} +B^{2}= C^{2}$

Plug the sides values into the equation.

$A^{2} + 13^2 = 20^2\\\\A^2 + 169 = 400\\\\A^2 = 231\\\\A = 15.1987$ <- This is the answer.

#teamtrees #PAW (Plant And Water)

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What is a irrational number between 12.1 and 12.2

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3 years ago

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The bulls-eye on a target has a diameter of 3 inches. The whole target has a diameter of 15 inches. What part of the whole targe

Helga [31]

Since a target is a circle and the bulls-eye is also a circle, the percent of the circle that is bulls-eye would be (Area of the bulls eye)/(Area of the target)

[tex] A = \pi r^{2} \\
d = 2r \\ r = \frac{d}{2} \\\\
\frac{ \pi ( \frac{d}{2})^{2}}{ \pi ( \frac{d}{2})^{2} }= \frac{ \pi ( \frac{3}{2})^{2}}{ \pi ( \frac{15}{2})^{2} }\\
\frac{ \pi ( \frac{3}{2})^{2} }{ \pi ( \frac{15}{2})^{2} } = \frac{ \pi (1.5)^{2} }{ \pi (7.5)^{2} } \\
\frac{ \pi (1.5)}{ \pi (7.5) } = \frac{ \pi (2.25)}{ \pi (56.25)}\\
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So the bulls-eye takes up 4% of the target.

4 0

3 years ago

PLEASE HELP QUICK! I'M OFFERING 25PTS & BRAINLIEST ANSWER (Its only worth 10pts) I just need this done PLEASE SHOW YOUR WORK

LenaWriter [7]

QUESTION 1

The dimensions of the rectangular blanket are;

$l = (3x + 7)cm$

and

$w = (2x - 3)cm$

The perimeter is given by,

$p= 2w + 2l$

We substitute the dimensions to obtain,

$p = 2(2x - 3) + 2(3x + 7)$

Expand bracket to get,

$p = 4x - 6 + 6x + 14$

This simplifies to
$p =( 10x + 8 )cm$

QUESTION 2

When

$x = 4$
The perimeter becomes

$p =( 10(4) + 8 )cm$

$p =( 40 + 8 )cm$

$p =48cm$

QUESTION 3

Area is given by

$A=l \times w$
$A=(3x + 7)(2x - 3)$

We expand to get,

$A=6 {x}^{2} - 9x + 14x - 21$

This gives us,

$A=(6 {x}^{2} + 5x - 21) {cm}^{2}$

QUESTION 4

If
$x = 4$
Then the area becomes,

$A=6 {(4)}^{2} - 9(4)+ 14(4) - 21$

$A=6 \times 16 - 36+ 56- 21$

$A=96 - 36+ 56- 21$

$A=95 {cm}^{2}$

QUESTION 5.

When the length of the blanket is 5cm longer, then the length of the new blanket becomes

$l = (3x + 7 + 5)$

$l = (3x + 12)cm$

The width is still

$w = (2x - 3)cm$

The perimeter of the new blanket is

$p = 2(3x + 12) + 2(2x - 3)$

This implies that,

$p = 6x + 24+ 4x - 6$

$p = 10x +18$

Comparing to the old perimeter which is

$p = 10x +8$ ,

The perimeter changes by 10 units

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3 years ago

What is the recursive formula for this geometric sequence?–2, –16, –128, –1024, ...

Tatiana [17]

Answer:

$b_n=-2\cdot 8^{n-1}$