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abruzzese [7]
3 years ago
13

https://lh5.googleusercontent.com/BTB8IVPp1M9ftWYrmUv4V29JTOIu-fUaQRDbERGKuRvHwen-iiK29m3v1rhGvp6kX40Rv0TBORmiPdtdKLoAv9vuG5Hp5Z

yxagl7seoinGhvF_GybYwC6CUpHVb5=w621
Mathematics
2 answers:
marshall27 [118]3 years ago
8 0

Answer:

it won't let me see the link

Verdich [7]3 years ago
5 0

Answer:

Option H, 1.428 * 10^-3

Step-by-step explanation:

<u>Step 1:  Convert 0.001429 into scientific notation</u>

To have the number in scientific, you need to have to have a number then the decimal point then the rest of the numbers.

0.001429

<em>1.429</em>

<em />

<u>Next, you need to find out what you multiply 1.429 to get 0.001429</u>

1.429 * 0.001

<em>1.428 * 10^-3</em>

<em />

Answer:  Option H, 1.428 * 10^-3

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1
zmey [24]

Answer:

Part 1) The inequality that represent this situation is 5(x+7)^{2} \geq1,050  or  5x^{2}+70x+245 \geq1,050

Part 2) Yes, 8 inches is a reasonable width for his tablet

Step-by-step explanation:

Part 1)

Let

L -----> the length of the screen television

W ----> the width of the screen television

x ---->  the width of Andrew's tablet

we know that

L=5W ------> equation A

W=x+7 ----> equation B

The area of the television is

A=LW -----> equation C

Substitute equation A and equation B in equation C

A=5(x+7)(x+7)

A=5(x+7)^{2}

5(x+7)^{2} \geq1,050

5(x^{2}+14x+49) \geq1,050

5x^{2}+70x+245 \geq1,050 ------> inequality that represent this situation

Part 2) Determine if 8 inches is a reasonable width for his tablet

For x=8 in

Substitute in the inequality

5(8+7)^{2} \geq1,050

5(15)^{2} \geq1,050

1,125 \geq1,050 -----> is true

therefore

Yes, 8 inches is a reasonable width for his tablet

3 0
3 years ago
If 75 is 25% of a value, what is that value?
sertanlavr [38]
75÷25%
25%=0.25
75÷0.25
=300
Your answer is 300
7 0
4 years ago
A sixth number will be added to the list. What must it be in order for the mean to be 12?
Nataliya [291]
The sixth number should be 16 in order for the mean to be 12
7 0
3 years ago
Read 2 more answers
PLS SOMEONE HELP ME
Anarel [89]
A and D are 85 degrees
4 0
3 years ago
Two squares have areas of 4 cm?
timofeeve [1]

Answer:

1/2

Step-by-step explanation:

First square area = 4cm^2, thus the side length is 2cm

Second square area = 16cm^2, thus the side length is 4cm

This gives a ratio of 2/4, simplifying yields 1/2

3 0
2 years ago
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