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2 years ago

The upper quartile of a set of data is the mode of the upper half of the data.true or false

Mathematics

2 answers:

Bad White [126]2 years ago

8 0

False, the upper quartile of a set of data is the median, not the mode

Alja [10]2 years ago

8 0

Answer:

Hi there!!! The answer would be False. I hope that I helped

Step-by-step explanation:

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Marissa bought 3 movies for $9.99 each and 2 video games for $14.99 each. These prices included tax .she gives the cashier $70.0

oksian1 [2.3K]

Answer:

10.05

Step-by-step explanation:

9.99+9.99+9.99+14.99+14.99

=59.95

70-59.95

=10.05

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2 years ago

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The ratio of dogs to cats at a local animal shelter is 13/25. Which statement must be true?

Alinara [238K]

$\bf \cfrac{dogs}{cats}\qquad \stackrel{ratio}{\cfrac{13}{25}}\qquad \cfrac{\leftarrow \textit{for every 13 dogs}}{\leftarrow \textit{there are 25 cats}}$

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3 years ago

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How do I write an algebraic equation for this word problem?

Doss [256]

Hi.

Please note that I haven't done much algebra.

4 more = 4 +

Twice as many than the runner up means 2 times the amount they ate (a variable) = 2n

So far we have 4 + 2n

Since it's an equation, we are going to know what it equals. In the problem, we find out that it's 11. So the equation looks like this:

4 + 2n = 11

If this didn't work out, please let me know.

~

I believe n = 3.5

7 0

2 years ago

❊ Simplify :

DiKsa [7]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to simplify:

$\displaystyle \frac{a+2}{a^2+a-2}+\frac{3}{a^2-1}$

First, let's factor the denominators of each term. For the second term, we can use the difference of two squares. Hence:

$\displaystyle =\frac{a+2}{(a+2)(a-1)}+\frac{3}{(a+1)(a-1)}$

Now, create a common denominator. To do this, we can multiply the first term by (a + 1) and the second term by (a + 2). Hence:

$\displaystyle =\frac{(a+2)(a+1)}{(a+2)(a-1)(a+1)}+\frac{3(a+2)}{(a+2)(a-1)(a+1)}$

Add the fractions:

$\displaystyle =\frac{(a+2)(a+1)+3(a+2)}{(a+2)(a-1)(a+1)}$

Factor:

$\displaystyle =\frac{(a+2)((a+1)+3)}{(a+2)(a-1)(a+1)}$

Simplify:

$\displaystyle =\frac{a+4}{(a-1)(a+1)}$

We can expand. Therefore:

$\displaystyle =\frac{a+4}{a^2-1}$

Problem 2)

We want to simplify:

$\displaystyle \frac{1}{(a-b)(b-c)}+\frac{1}{(c-b)(a-c)}$

Again, let's create a common denominator. First, let's factor out a negative from the second term:

$\displaystyle \begin{aligned} \displaystyle &= \frac{1}{(a-b)(b-c)}+\frac{1}{(-(b-c))(a-c)}\\\\&=\displaystyle \frac{1}{(a-b)(b-c)}-\frac{1}{(b-c)(a-c)}\\\end{aligned}$

Now to create a common denominator, we can multiply the first term by (a - c) and the second term by (a - b). Hence:

$\displaystyle =\frac{(a-c)}{(a-b)(b-c)(a-c)}-\frac{(a-b)}{(a-b)(b-c)(a-c)}$

Subtract the fractions:

$\displaystyle =\frac{(a-c)-(a-b)}{(a-b)(b-c)(a-c)}$

Distribute and simplify:

$\displaystyle =\frac{a-c-a+b}{(a-b)(b-c)(a-c)}=\frac{b-c}{(a-b)(b-c)(a-c)}$

Cancel. Hence:

$\displaystyle =\frac{1}{(a-b)(a-c)}$

4 0

2 years ago

Write the equation of a line that passes through the points ( 2 , - 5 ) and ( 8 , - 2 )

kati45 [8]

Answer:

$y=\frac{1}{2}x-6$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)