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alina1380 [7]
3 years ago
6

The upper quartile of a set of data is the mode of the upper half of the data.true or false

Mathematics
2 answers:
Bad White [126]3 years ago
8 0
False, the upper quartile of a set of data is the median, not the mode
Alja [10]3 years ago
8 0

Answer:

Hi there!!! The answer would be False. I hope that I helped

Step-by-step explanation:

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Writey=1/8 x+7 in standard form using integers.
sineoko [7]

Answer:

x - 8y = - 56

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y = \frac{1}{8} x + 7

Multiply through by 8 to clear the fraction

8y = x + 56 ( subtract 8y from both sides )

0 = x - 8y + 56 ( subtract 56 from both sides )

- 56 = x - 8y, that is

x - 8y = - 56 ← in standard form

5 0
4 years ago
I'm really confused, can someone please help me with this problem?
stiv31 [10]

Answer: x = 6.25

5 ÷ 0.8

= 6.25

6 0
3 years ago
What is the simpified ratio of 12 cups to 2 pints
jeyben [28]
6 pints in 12 cups Hope this helps!
8 0
4 years ago
Read 2 more answers
What is a number that when you subtract it by 8 and then multiply by 7 will equal to 28?
Aleks04 [339]

Answer:

n = 12

Step-by-step explanation:

(n-8)x 7 = 28

n-8 = 4

n = 12

5 0
3 years ago
Read 2 more answers
Find the HCF of 960 and 432​
sdas [7]

Answer:

48

Step-by-step explanation:

Using Uclid's division algorithm, the HCF of 960 and 432 can be obtained as follows:

Here, 960 is greater and 432 is smaller. We divide 960 by 432.

STEP 1:

960 = 432*2 + 96

STEP 2:

Divide divisor (432) by remainder (96)

432 = 96 * 4 + 48

STEP 3:

Divide divisor (96) by remainder (48)

96 = 48 * 2 + 0

Since, remainder at this step is zero (0), so the HCF would be the divisor of this step which is 48.

Thus, HCF of 960 and 432 is 48

4 0
3 years ago
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