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3 years ago

The solution to a problem is an irrational number. Which statement is true about the solution?

Mathematics

1 answer:

navik [9.2K]3 years ago

6 0

Group of answer choices.

A. It can be expressed as a non repeating, non terminating decimal.

B. It can be a perfect square

C. It cannot be pie π

D. It is not possible to have a irrational number solution.

Answer:

A. It can be expressed as a non repeating, non terminating decimal.

Step-by-step explanation:

An irrational number can be defined as real numbers that cannot be expressed as a simple fraction or ratio of two integers.

Additionally, it is the opposite of a rational number and as such its decimal is continuous without having any repetition or termination. For example, pie (π) = 3.14159 is an example of an irrational number.

Assuming the solution to a mathematical problem is an irrational number. The statement which is true about the solution is that it can be expressed as a non-repeating, and non-terminating decimal.

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Margarita [4]

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Step-by-step explanation:

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3 years ago

prism x is showen below. the volume of prism y is 10 cubic cm greater than the volume of prism x. what is the volume of prism y.

Vlad1618 [11]

Answer:

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Then use that product and times it by 10. ( 10 x 30 )

Ans = 300 cubic centimeters

Step-by-step explanation:

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1 year ago

The graph models the daily high temperature, H(t), in Santiago, Chile, t days after the hottest day of the year. What does the p

alekssr [168]

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H (t)
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Answer:
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3 years ago

Write the phrase as an expression. Then evaluate the expression when x = 5.

Nadusha1986 [10]

Answer:

6 + 8x

Step-by-step explanation:

1. Write the expression

6 + 8x

2. Plug in 5 for x

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2 years ago

200 σ j=1 2j( j 3) describe the steps to evaluate the summation. what is the sum?

ziro4ka [17]

The sum of the equation is = 5494000.

<h3>What does summation mean in math?</h3>

The outcome of adding numbers or quantities mathematically is a summation, often known as a sum. A summation always has an even number of terms in it. There may be just two terms, or there may be 100, 1000, or even a million. Some summations include an infinite number of terms.

<h3>Briefing:</h3>

Distribute 2j to (j+3).

Rewrite the summation as the sum of two individual summations.

Evaluate each summation using properties or formulas from the lesson.

The lower index is 1, so any properties can be used.

The sum is 5,494,000.

<h3>Calculation according to the statement:</h3>

$\sum_{j=1}^{200} 2 j(j+3)$