<h3>
Answer: sometimes true</h3>
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Explanation:
The plane P can be thought of a perfectly flat ground. Now imagine a flag pole which represents line GH. If AB is drawn in chalk on the pavement, and this line AB intersects the base of the flagpole, then we've made AB and GH intersect. However, this example shows that GH is <u>not</u> on the plane P.
Is it possible to have GH be in the the plane? Yes. We could easily draw another chalk line on the ground to have it intersect AB somewhere. But as the previous paragraph says, it's also possible that GH is not in the plane.
Therefore, the statement is sometimes true
The correct option about the proof is C. Both Amanda and Stephen are correct.
<h3>How to illustrate the information?</h3>
It should be noted that both Amanda and Stephan are correct as they are taking two different pairs of supplementary angles.
Amanda's proof is that he takes (∠1 and ∠4) and (∠3 and ∠4)as the supplementary angles and writes ∠1 + ∠4 = 180° and ∠3 + ∠4 = 180°,
Stephan's proof is that he takes (∠1 and ∠2) and (∠3 and ∠4) as the <em>supplementary</em> angle pair.
Therefore, the correct option is C.
Learn more about proof on:
brainly.com/question/1788884
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It would be 0.
5 times zero is zero, adding 6 will make it equal to 6.
Hope this helped broski
Answer:
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Step-by-step explanation:
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