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Doss [256]
3 years ago
15

Convert to cups. 9 quarts

Mathematics
1 answer:
arsen [322]3 years ago
7 0
36 cups ........................................

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E - 867 = 108; E = need help
lina2011 [118]
To solve for E you'll add 867 to 108.

E - 867 = 108
E = 108 + 867
E = 975

Hope this helps :)

7 0
3 years ago
Determine whether the graphs of 7= 5x+9 and -y = -5x -9 are parallel, perpendicular, coincident, or none of these.
3241004551 [841]
Assuming your first equation is y = 5x+9, the equations describe lines that are coincident.

_____
Multiplying the second equation by -1, it becomes y = 5x+9, the same as the first equation.
6 0
3 years ago
3x - 3y = -15<br> -x + y = 5
Katyanochek1 [597]

Answer:

I don't understand what you're asking. can you put a question on this?

4 0
3 years ago
Volume of a cylinders​
const2013 [10]

Answer:

The volume of cylinder is V=πr^2h

7 0
2 years ago
At a local University, it is reported that 81% of students own a wireless device. If 5 students are selected at random, what is
Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

81% of students own a wireless device.

This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

34.87% probability that all 5 have a wireless device

5 0
3 years ago
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