Solve -6|2x-9|+1=-17 and give the final answers that would make the equations true

1 answer:

6 0

Remember
if |x|=y
assume
x=y and -x=y or
x=y and x=-y

so

-6|2x-9|+1=-17
minus 1 from both sides
-6|2x-9|=-18
divide both sides by -6
|2x-9|=3
assume
2x-9=3 and2x-9=-3
solve

2x-9=3
add 9
2x=12
divide 2
x=6

2x-9=-3
add 9
2x=6
divide 2
x=3

x=3 and/or 6

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To solve: Let's solve your equation step-by-step.

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Step 1: Simplify both sides of the equation.

4x2+4x=2004

Step 2: Subtract 2004 from both sides.

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4x2+4x−2004=0

Step 3: Use quadratic formula with a=4, b=4, c=-2004.

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4 0

3 years ago

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Genrish500 [490]

We have that

$\frac{(x+4)}{3} / \frac{6}{x} = \frac{x*(x+4)}{3*6} \\ \\ = \frac{( x^{2} +4x)}{18}$

therefore

case a)
$\frac{(x+4)}{3} * \frac{x}{6}$
Is equivalent

case b)
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Is not equivalent

case c)
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Is equivalent

case d)
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Is not equivalent

case e)
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Is equivalent

Hence

the answer is

$\frac{(x+4)}{3} * \frac{x}{6}$

$\frac{x}{6} * \frac{(x+4)}{3}$

$\frac{(2 x^{2} +4x)}{18}$

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