All categories

4 years ago

Claire jogs no more than 20 miles per week. Which inequality represents the number of miles she runs each week?

2 answers:

7 0

With this problem, the wording is important. “Claire jogs NO MORE than 20 miles per week” this means that she can run 20 miles or less.

Final answer
D if x is the miles per week

anzhelika [568]4 years ago

3 0

C Claire hogs anywhere between 0 and 20 miles per week. So she jogs 20 and below. Making the answer c

You might be interested in

Who is Lonely at the current moment....and not busy?

sergejj [24]

hAHAHahah haHaHrwahrahweha

5 0

3 years ago

A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago

PLEASE HELP: Find the measure of the angle indicated. Arc BC is 80 degrees.

Marina CMI [18]

The angle is 80 degrees. The measure of an angle is the exact same as the angle measure of the included arc, so that makes angle BAC 80 degrees

7 0

3 years ago

Jamal planted 53 fewer flowers than Heidi. Write an expression to show how many flowers Heidi planted.

Sergeu [11.5K]

Answer:

y = x + 53

Step-by-step explanation:

Let x be the number of flowers Jamal planted and y the number of flowers Heidi planted.

Jamal planted 53 fewer flowers than Heidi:

x = y - 53

Isolate the y.

x + 53 = y (Change the - sign to + sign when switching from different sides of an equation)

y = x + 53

6 0

3 years ago

Read 2 more answers

2 members of the 5-member math study group will present their project to the class. How many combinations of 2 members are possi

klio [65]

Answer:

Step-by-step explanation:

(,)=?

(,)=(5,2)

=5!(2!(5−2)!)

=5!2!×3!

= 10

4 0

3 years ago