Answer: B
Explanation: I’ve taken this test before and got it right :)
If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Take 2 points
Slope:-

Equation in point slope form


- Initial amount=y intercept=5000
What you have written down is correct, x=-3